Author: ADMIN
Editorialist: SUSHANT AGARWAL
CAKEWALK
Basic looping,Basic Input/Output
Rewrite small numbers from input to output. Stop processing input after reading in the number 42. All numbers at input are integers of one or two digits.
Please refer to the sample solution given by editorialist.
Editorialist’s solution can be found here.
#include<iostream.h>
void main()
{
int a,flag=0;
do
{
cin>>a;
if(a<=99 && a>=(-99) && a!=42)
{
flag=1;
cout<<a;
}
}while(flag==1);
}import java.util.*;
public class inToOut{
public static void main(String [] args)
{
Scanner in = new Scanner(System.in);
while(in.hasNextInt() )
{
int temp = in.nextInt();
if(temp == 42)
break;
System.out.println(temp);
}
}
}
#include<stdio.h>
int main()
{int i,b[100];
for(i=0;i<100;i++)
{scanf("%d\n",&b[i]);
if(b[i]==42)
break;
else
printf("%d\n",b[i]);
}
return 0;}
#include<stdio.h>
int main()
{
int a=1;
while(a>=(-99) && a<=99)
{
scanf("%d",&a);
if(a!=42)
printf("%d\n",a);
else
break;
}
return 0;
}
#include<stdio.h>
#include<conio.h>
void main()
{
int x;
printf("\n Enter a two digit no to stop enter 42 “);
scanf(”%d",&x);
if((x>99)||(x=42))
break;
else
printf(“the entered no is : %d”,x);
}
#include<stdio.h>
main()
{
int num=0;
while(num<100)
{
scanf("%d",&num);
if(num!=42)
printf("%d",num);
else
continue;
}
/this is corect answer even tho sowing false/
#include <stdio.h>
int main ()
{
int n;
for (;n!=42;)
{
scanf ("%d",&n);
printf ("%d\n",n);}
return 0; }
import java.util.Scanner;
public class LifeTheUniverseAndEverything {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while (true) {
int i = scanner.nextInt();
if (i == 42)
break;
System.out.println(i);
}
}
}
#include<stdio.h>
int main(void)
{
unsigned int num;
for(;printf("%d",scanf("%d",&num)!=42););
return(0);
}
import java.util.Scanner;
/**
*
@author Avi
*/
public class New {
/**
@param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
int poda[];
poda = new int[10];
Scanner input = new Scanner(System.in);
System.out.println(“enter the array”);
for (int i =0;i<5;i++)
{
poda[i]=input.nextInt();
}
System.out.printf("the output values are ");
for (int i =0;i<5;i++)
{
if(poda[i]==42)
{
break;
}
System.out.println(poda[i]);
}
}
}
void main()
{
int i,a[6];
a[6]={1,42,84,7,8,9};
for(i=0;i<6;i++)
{
if(a[i]<=a[i+1])
{printf("%d",a[i]);
printf("\n");
}else
break;
}
getch();
}
#include<iostream.h>
using namespace std;
main()
{
int n;
cout<<“enter a number”;
cin>>n;
while(n>-99 && n<99 && n!=42)
{
cout<<“enter a no.”
cin>>n;
cout>>n;
}
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
while(1)
{
printf(“Enter the number:”);
scanf("%d",&n);
if(n==42)
break;
printf("%d",&n);
}
}
my program is having a compile error:
package codechef;
import java.util.Scanner;
public class chef {
private static Scanner input;
public static void main(String[] args) {
input = new Scanner(System.in);
int value = 0 ;
do{
System.out.println("Enter a number: ");
value = input.nextInt();
System.out.println(value);
}
while(value != 42);
System.out.println("Program terminated");
}
}
package package1;
import java.util.Scanner;
public class Class1 {
public static void main(String[] args) throws Exception {
while(true)
{
System.out.println("Enter an integer");
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
if( (num<100) && (num>(-100)) && (num!=42) )
System.out.println(num);
else
return;
}
}
}
using namespace std;
int main()
{
int i;
do
{
cout << "Enter i : ";
cin >> i;
if (i==42 && i<100 && i>-100)
{
break;
}
else
{
cout << i;
}
} while (i != 42 && i<100 && i>-100);
return 0;
}
#include< iostream >
#include< conio.h >
using namespace std;
int main()
{
int a[1000],i;
cout <<“enter integers” << endl;
for( i=1 ; i<=1000 ; i++ )
{
cin >> a[i];
if ( a[i]==42 )
{
break;
}
}
getch ();
return 0;
}
#include<stdio.h>
main()
{
int a[100],i;
printf(“enter numbers and enter 42 to end”);
for(i=0;i<100;i++)
{scanf("%d",&a[i]);if(a[i]==42)break;else printf("%d",a[i]);}
}
//C Solution by satadru97
#include<stdio.h>
int main(void)
{
int n;
while(1)
{
scanf("%d",&n);
if(n!=42)
printf("%d\n",n);
else
break;
}
return 0;
}