Doubt in AEHASH

In this problem why they have taken max(V1, V2) = V - A ? I tried understanding but in vain. Can someone explain ?

I think its just a simple re-arrangement.

I mean, V= result (variable returned by function)

And-

result = result + max(hash(S1), hash(S2))

But before this, result =A (we defined it such)

==> Result = A+max(v1,v2)

==>V=A+max(v1,v2)

Hence, max(v1,v2)=V-A.

They just shuffled the terms here and there. That editorial was kinda hard to understand…idk if its because of my sleepiness atm or what.

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perfect…