hexa decimal number addition in java

general
1

input 2 hexadecimal numbers and then add them and print the result without any conversion to decimal .we have to code as we simply add them in reality

2

It can be done in O(n) approach where n is number of digits in hexadecimal number…

One of the way is using if else statements and adding them…
I can explain you in a bit detail If u tell me about input format and the constraint for number of digits…

3

import java.math.BigInteger;

class BI
{
	public static void main (String[] args) throws java.lang.Exception
	{
	    BigInteger bi1 = new BigInteger("aBc", 16);
	    BigInteger bi2 = new BigInteger("DeF", 16);
	    BigInteger bi3 = bi1.add(bi2);
	    System.out.println(bi3.toString(16));
	}
}

Why settle for hexa decimals when you can perform calculations on a 36-base number??

4

moreover tell me If you are using abcdef or ABCDEF or it can be anything from both of them…

5

so do you think Biginteger class won’t convert them in any other base ?? cuz he isn’t allowed to change the base…

6

Yes, you can always code the whole process yourself. I just tried to point out that there is already a very useful Java library class to take care of hexadecimals and other number systems.

1 Like
7

Okay that’s nice…

8

Thanks for answering