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# ACTNBM – Editorial

Author: Arkapravo Ghosh
Tester: Aparup Ghosh
Editorialist: Aparup Ghosh

CAKEWALK

# PREREQUISITES:

Basic programming, conditionals

# PROBLEM:

Given two integers S and H you need to output “Shinchan” if S > H or “Himawari” otherwise.

# QUICK EXPLANATION:

According to the given conditions, Shinchan can only win when S is greater than H. In any other case, Himawari is the winner.

# EXPLANATION:

We can simply check if S is greater than H or not. If S > H, then we output “Shinchan”(without quotes) else (i.e. when S <= H), we output “Himawari”(without quotes).
The time complexity is O(T).

# AUTHOR'S AND EDITORIALIST'S SOLUTIONS:

Author's solution can be found here.
Editorialist’s solution can be found here.

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accept rate: 0%

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 0 for _ in range(int(input())): S, H = [int(x) for x in input().split()] print(["Himawari","Shinchan"][S>H])  answered 17 Aug '18, 18:29 1★teratau 11 accept rate: 0%

# include<stdio.h>

void main() { int s,h; printf("\n Enter the two no= "); scanf("%d%d",&s,&h); printf("\n S=%d",s,"\n H=%d",h); if(s>h) { printf("\n Sinchan"); } else { printf("\n Himawari"); } }

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question asked: 07 Aug '18, 00:56

question was seen: 254 times

last updated: 16 Aug '18, 00:34