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# how to solve MARVEL BOX?

 0 problem link. Can someone please share their approach. asked 11 Oct, 07:46 3★pk301 627●10 accept rate: 16% there are only 2 cases possible (x,x,x,a+b+c=x) (x,x,a+b=x,c+d=x) for 1st: so lets just go through all possible x, find number of ways such that a+b+c=x,lets say it is val so ans of first type ans1=((no.of.x)C3)*val for 2nd: lets just go through all possible x, find number of ways of ways of choosing 4 numbers a,b,c,d such that ((a+b)=x and (c+d)=x) or ((a+c)=x and (b+d)=x) or ((a+d)=x and (b+c)=x) let this be val3 so ans of second type ans2=((no.of.x)C2)*val2 res=ans1+ans2 try thinking of some dp for val,val3..... (11 Oct, 22:44) can you explain the dp states? I tried but didn't get it :( (19 Oct, 20:44) pk3013★
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