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Runtime Error(SIGSEGV)

MY Program is giving Runtime Error(SIGSEGV).what does it mean???

asked 01 Aug '13, 09:50

saanc's gravatar image

5★saanc
6505721
accept rate: 0%

edited 24 Aug '15, 09:59


SIGSEGV Error is caused by an invalid memory reference or segmentation fault. The most common causes are accessing an array element out of bounds, or using too much memory. Check this link for more clarity.

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answered 01 Aug '13, 12:09

sobhagya's gravatar image

3★sobhagya
2.7k132747
accept rate: 12%

This type of problem generally comes due to array out of index problem.if such problem occurs see your loop consisting array index .happy coding. :)

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answered 01 Oct '16, 23:24

panjiara2114's gravatar image

2★panjiara2114
11
accept rate: 0%

Hi A SIGSEGV is an error(signal) caused by an invalid memory reference or a segmentation fault. You are probably trying to access an array element out of bounds or trying to use too much memory. Some of the other causes of a segmentation fault are : Using uninitialized pointers, dereference of NULL pointers, accessing memory that the program doesn’t own.

source- codechef status code page

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answered 02 Oct '16, 14:31

smsubham's gravatar image

3★smsubham
674216
accept rate: 15%

I am also receiving the same problem. My code works for the CLEANUP task. I have checked on IDEONE.com too and it also compiled it successfully. I couldn't find any solution .Plz hellp!! MY CODE:

#include<stdio.h>
using namespace std;
int main(){
    int t;
    scanf("%d", &t);
    if(t>50) return 0;
    for(int j=0;j<t;j++){
        int n,m,a,flag=0;
        scanf("%d%d", &n, &m);
        if(m<0 || m>n || n>1000) return 0;
        int arr[n]={0};
        for(int i=0;i<m;i++){
            scanf("%d",&a);
            arr[a-1]=-1;
        }
        for(int i=0;i<n;i++){
            if(arr[i]==-1) { flag++; }
            else { arr[i] = i-flag; }
        }
        for(int i=0;i<n;i++){
            if((arr[i]>-1) && (arr[i]%2==0)) {printf("%d ",i+1);}
        }
        printf("\n");
        for(int i=0;i<n;i++){
            if((arr[i]>-1) && (arr[i]%2==1)) {printf("%d ",i+1);}
        }
        printf("\n");
    }
    return 0;
}
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answered 07 Apr '17, 00:53

tript's gravatar image

2★tript
1
accept rate: 0%

edited 08 Apr '17, 18:41

vijju123's gravatar image

4★vijju123 ♦♦
15.2k11859

i am using arr size of n elements specified by the user and if i was accessing any element out of bounds i'd have received an error while it on other platforms too, but i didn't.

(08 Apr '17, 15:36) tript2★

Fixed the formatting.

(08 Apr '17, 18:41) vijju123 ♦♦4★

int arr[n]={0};

I doubt this statement is allowed....not sure tho.

(08 Apr '17, 18:53) vijju123 ♦♦4★

It is allowed, it initiallizes arr with 0 @vijju @tript change the loop where you scanf to i=0;i<n;i++ it ll probably fix it, if it doesn't declare a global array for being on the safe side.

(09 Apr '17, 01:05) neilit19923★

Not sure. I distinctly remember using that statement once but it didn't let me. And I had to use a loop to initialise it. I guess it must be that compiler in this case. Thanks for info @neilit1992 :)

(09 Apr '17, 02:07) vijju123 ♦♦4★

It occurs when you access an element which is out of bound / else using too much memory

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answered 07 Apr '17, 03:57

aashutosh001's gravatar image

3★aashutosh001
61
accept rate: 0%

https://www.codechef.com/viewsolution/14108863 can someone pls help me with this one?I am a beginner and stuck in this for a while.I have checked all the possibilities for runtime error but cud nt find any. Thanks question : https://www.codechef.com/JUNE17/problems/CLONEME

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answered 06 Jun '17, 18:23

akriti17's gravatar image

2★akriti17
1
accept rate: 0%

its against rules to discuss problems of live contest......! @akriti17 however runtime error is caused due to 1.using large memory(or declaring large sized arrays) ..!! (for dis u have to declare large sized arrays globally like array[1000000].....) 2.accessing elements out of bounds i.e. accessing elements which are not declared !! happy coding :)

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answered 06 Jun '17, 18:32

msd_007's gravatar image

1★msd_007
3178
accept rate: 5%

@tript,

 for(int i=0;i<m;i++){
            scanf("%d",&a);
            arr[a-1]=-1;
        }

This arr[a-1] can cause segmentation fault , check the bounds on a

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answered 06 Jun '17, 21:55

gagan86nagpal's gravatar image

5★gagan86nagpal
11116
accept rate: 11%

edited 06 Jun '17, 21:55

You are accessing any index which is out of the bounds. Try to resolve the problem by carefully looking into the code . Happy Coding

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answered 01 Sep '17, 03:07

aps8601378765's gravatar image

2★aps8601378765
1
accept rate: 0%

include <iostream>

include<bits stdc++.h="">

include <math.h>

using namespace std;

int main() { int n,k,sum=0;long a[100005]; // your code goes here cin>>n>>k; if(n>=1 && k<pow(2,100000)){ for(int i =0;i<k;i++) { a[i]=1; sum+=a[i]; } a[k]=k; int t; for(int p=k+1;p<=n;p++) { t=0; for(int j=1;j<=k;j++) { t=t+a[p-j]; } a[p]=t;//%1000000007; } //cout<<a[n]<<endl;

/for(int l=0;l<n;l++) { cout<<"\t"<<a[l]; }/ cout<<a[n-1]%1000000007; } return 0;

}

for the above code i'm getting SIGSEGV error when i try to submit. Can someone please help ?

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answered 23 Jan '18, 15:41

shraddha0706's gravatar image

0★shraddha0706
1
accept rate: 0%

does declaring an array of size 1000000 give a SIGSEGV because it occupies only 4MB (array type long long int)

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answered 07 Oct '18, 17:40

dsai_2000's gravatar image

2★dsai_2000
1
accept rate: 0%

I am also receiving the same problem. I have checked on IDEONE.com too and it also compiled it successfully. I couldn't find any solution. It compiled sucessfully everywhere locally as well as on every online platform . But when I submit code it is showing same error as above .Plz hellp!! MY CODE:

include<bits stdc++.h="">

using namespace std; int main()

{ long long t; cin>>t; while(t--) { long long n,p,i,x=0,max=0,j,k,q,a; vector<long long="">arr; cin>>n>>p; for(i=1;i<=p;i++) { a=n%i; if(a!=0&&a<n) arr.push_back(a); }

   sort(arr.begin(),arr.end(),greater<int>());
    max=arr.front();
    for(i=1;i<=p;i++)
    {
        for(j=1;j<=p;j++)
        {
            for(k=1;k<=p;k++)
            {

                if(max==(((n%i)%j)%k)%n)
                x++;
            }
        }
    }
    cout<<x;
}

}

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answered 07 Jan, 09:34

rishabh_garg1's gravatar image

2★rishabh_garg1
1
accept rate: 0%

edited 07 Jan, 09:36

This type of error(segmentation fault) means that you are using an undefined memory and accessing it somewhere mostly in loops.

**Most of the time you need to declare an array of a[n+1] instead of a[n] bcz u loop i from 1 to n.

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answered 11 Jan, 00:36

palak2001's gravatar image

2★palak2001
11
accept rate: 0%

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question asked: 01 Aug '13, 09:50

question was seen: 46,720 times

last updated: 11 Jan, 00:36