can any one tell me what is wrong with my solution for The ATM problem.
/* Program to solve ATM problem on codechef
Author: Monjyoti Das
*/
#include<stdio.h>
int main(){
float bal;
int withdraw_amt;
printf("Input:(amount to withdraw & balance):");
(void)scanf("%d %f",&withdraw_amt, &bal);
if((float)withdraw_amt >= bal) {
printf("\nInsufficient Funds.\nOutput: %.2f\n",bal);
return 0;
}
if(withdraw_amt % 5 == 0) {
bal = bal-(float)0.50-withdraw_amt;
printf("\nOutput:\n %.2f\n",bal);
}
else {
printf("\nIncorrect Withdrawl Amount(not multiple of 5)\n Output:\n %.2f", bal);
}
return 0;
}
Please don’t print messages in printf()
can some one tell me, what is the ATM problem? I’m new here.
1 Like
anickzz
September 1, 2014, 9:42am
4
What cool_techie is trying to tell you is that you should only print the balance as a number, without any text. Check the question spec and example output.
#include #include
//cin>>x>>y;
cin>>t;
while(t--){
cin>>z>>y;
x=z;
if(0<x&&x<=2000)
if(0<=y&&y<=2000)
if(x>y)
cout<<fixed<<setprecision(2)<<y;
else if(x%5!=0)
cout<<fixed<<setprecision(2)<<y;
else
cout<<fixed<<setprecision(2)<<y-x-0.50;
}
return 0;
}
#include <stdio.h>#include <stdlib.h>
int main()
}
#include <stdio.h>#include <stdlib.h>
int main()
}
there is no message in printf();