problem ATM Wrong answer

general
,
1

#include
#include<stdio.h>
using namespace std;
int main()
{
int amt;
float bal;
cin>>amt>>bal;
if(amt%5==0&&amt<bal)
{
bal=bal-amt-0.50;
}

    printf("%0.2f",bal);
    return 0;
}
2

Instead of if(amt%5==0&&amt<bal) , the condition should be if (amt % 5 == 0 && amt + 0.50 < bal).

3

@new_code_guru1 : You need to check “amt+0.5<=bal”

2 Likes
4

import java.io.;
import java.lang.;
import java.math.*;
import java.text.DecimalFormat;
class codechef2{
public static void main(String ar[])throws IOException{
DataInputStream dis=new DataInputStream(System.in);
String s=dis.readLine();
String str[]=s.split(" ");

float n = Float.parseFloat(str[1]);
float x = Float.parseFloat(str[0]);
DecimalFormat f = new DecimalFormat(“##.00”);

if((x%5==0)&&(n-x>=0.5))
{
System.out.println(f.format((n-x)-0.50));
}
else
System.out.println(f.format(n));

}
}

5

The program will fail if the input is 50 50.25.In this case it should not allow to withdraw.So include the condition in the if loop(bal-amt>0.50).

6

#include<stdio.h>
void main()
{
int amt;
float n,b2,bal;
scanf("%d %f",&amt,&bal);
if((amt%5!=0) || (bal-amt<0.5))
{
printf("\n%0.2f\n",bal);
}
else
{
n = bal-amt-0.5;
printf("\n%0.2f\n",n);
}

}

Whats wrong in this code?The website shows runtime error.

7

@itsmepsk why you are printing \n two times. And you must use int main() with return 0 statement. I think that’s the culprit here.

1 Like
8

@gautam94 : It should be “<=”

1 Like
9

@vineetpaliwal I got AC with if (amt % 5 == 0 && amt + 0.50 < bal) . Probably because it didn’t check for bal == amt + 0.50.

10

Thanks it worked.But what difference did it make?

11

In c++, you need an exit satement to know status of your program. And return 0 do that part.

12

@itsmepsk I don’t know about other programming languages but while submitting solutions in C and C++, all online judges require int main() instead of void main(). The former means that your main function returns an integer and hence at the end of the program you have to add the statement return 0;.

13

‘return 0;’ means that the program ran successfully without any error.

14

i did a few programs without the return statement and they worked !

15

whats the difference between return 0 and return 1;