@ rd13123013 When 010 or 101 comes at the last of the string ..then d=='\n' .Therefore ,it doesn't enters into While loop...so the count doesn't increasing .....and there lies the bug.

 So , you can overcome this by using "do() ...while()..loop" :)

Using Python's elegance http://www.codechef.com/viewsolution/3250941

for _ in xrange(input()):
    s = raw_input()
    if "010" in s or "101" in s: print "Good"
    else:                        print "Bad"

P.S.: Waiting for a one liner in Perl or GolfScript :P

UPDATE: If that's the case @shangjingbo, then how about a Perl regex check

$s =~ m/"101"/

Well, when I'm good with Monads I can return and fully solve this one in Haskell, but, the built-in functions sure are a charm:

isInfixOf "010" "10010"

:D

link text

@s_pandey01 It is in the checking stage. if '010' in j and '101' in j: it should use 'or' instead of 'and'. If 'and' is used, then 'Good' will only print out when both '010' and '101' are in the line.

@all:

May i know what is wrong with this approach. http://www.codechef.com/viewsolution/3177973

I was checking characters at i, i-1, i-2 in a loop.

Thanks :)

what is wrong wid this...

include <stdio.h>

include <conio.h>

include <string.h>

int main(void) { int t; char a , b , c ,d ,count ; scanf("%d" , &t); while(t--) { count = 0; a = getchar(); b = getchar(); c = getchar(); while( (d = getchar()) != '\n') ( (a=='0' && b=='1' && c=='0') || (a == '1' && b=='0' && c=='1')) ? ( (count++) , (a = b) , ( b = c) , (c = d )): ((a = b) , ( b = c), (c = d )); (count > 0)?(printf("Good\n")):(printf("Bad\n")); } getch(); return 0; }

int main() { int t; cin>>t; while(t--) { std::string str(""); cin>>str; if((str.find("010")==!std::string::npos) || (str.find("101")==!std::string::npos)) { cout<<endl<<"Good"<<endl; } else { cout<<endl<<"Bad"<<endl; } } system("pause"); return 0; }

What is wrong with this code? Similar code accepted in java but this is not working.

class Sample7

@t=0 @str

def initialize t=gets.to_i

for i in 0...t
  str=gets
  if str.include?"101"||"010"
    puts "Good"
  else puts "Bad"
  end
end

end end

obj=Sample7.new

WHAT IS WRONG IN MY CODE?

include<iostream>

include<string.h>

using namespace std; int main() { int t; long int l,i,c,d,j,e; cin>>t; while(t--) { char s[100005]; cin>>s;
l=strlen(s); for(i=0;i<l-2;i++) { e=2; c=0; j=i; while(e--) { if(s[j]!=s[j+1]) c++; else break; j++; } if(c==2) { cout<<"good"<<endl; break; } } if(c!=2) cout<<"bad"<<endl; } return 0; }

Guys can anyone tell what is wrong with this python code for the problem, according to me it is correct.....

lst=[]
a=int(input())
i=0
while i<a:
    str1=input()
    lst.append(str1)
    i=i+1

i=0

for j in lst:
    if '010' in j and '101' in j:
        print("Good")
    else:
        print("Bad")

Guys can anyone tell what is wrong with this python code for the problem, according to me it is correct.....

lst=[]
a=int(input())
i=0
while i<a:
    str1=input()
    lst.append(str1)
    i=i+1

i=0

for j in lst:
    if '010' in j and '101' in j:
        print("Good")
    else:
        print("Bad")

include<iostream>

include<string>

using namespace std; int main(){ int a; cin>>a; while(a--){ string s;int c=0; cin>>s; for(int i=0;i<(s.length()-1)&&c<2;i++){ if(s[i]!=s[i+1])c++; else c=0; } if(c==2)cout<<"Good"<<endl; else cout<<"Bad"<<endl; } return 0; }

import java.util.Scanner;
class untitled
{
public static void main(String[] args)
{
    Scanner kb=new Scanner(System.in);
    int test=kb.nextInt();
    while(test-->0)
    {
        String s1=kb.next();
        String s2="010";
        String s3="101";
        if(s1.contains(s2)||s1.contains(s3))
        System.out.println("Good");
        else
        System.out.println("Bad");          
    }
}
}

benefit of java!..... :-P