C program - explain output of following program

general
, ,
1

char *fun()
{
char *tmp = “SOME TEXT”;
return tmp;
}

void main()
{
puts(fun());
}

2

u need to use char pointer

char* fun()
{
const char* tmp="SOME TEXT";
return tmp;
}

void main()
{
puts(tmp);
}
3
  • little correction to the above program in which ranjan81 uses a pointer

char* fun()
{
const char* tmp=“SOME TEXT”;
return tmp;
}

void main()
{
puts(fun());// temp cant be used here
}

4

use pointer to store the value of string…

5

some garbage value is printed (or maybe segfault) since “temp” is destroyed as soon as we go out of its scope(which is function;s scope), so “temp” cant be accessed outside