BUY1GET1 - Editorial

editorial
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2

PLEASE TELL ME THE PROBLEM IN THE FOLLOWING CODE

#include <stdio.h>
int main()
{
    int t, i, len, co=0, h, y, a=0, cost[100], tem=0;
    char s[200], alp, x[]="qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM";
    scanf("%d", &t);
    for(i=1; i<=t; i++){
	co=0;
	scanf("%s", s);
	//printf("%c", s[0]);
	len=strlen(s);
	for(h=0; h<=51; h++){
	    alp=x[h];
	    a=0;
	    for(y=0; y<len; y++){
		if(s[y]==alp){
		    a++;
		}
	    }
	    if(a % 2 == 1){
		a=(a/2)+1;
	    }
	    else{
		a=a/2;
	    }
	    co=co+a;
	}
	cost[tem]=co;
	tem++;

    }
    for(tem=0; tem<t; tem++){
	printf("%d\n", cost[tem]);
    }
return 0;
}

THANKS IN ADVANCE
EAGERLY WATING FOR REPLY

3

http://www.codechef.com/viewsolution/1808761

whats wrong with this solution??

4

http://www.codechef.com/viewsolution/1835815

what’s the problem with this logic???

5

@abhashksingh : The ascii value of ‘a’ is 97 and not 71. Just think ‘A’ is 65 so next 25 values will be for upper case letters , so how can lower case letters start at 71 . Thats the bug in your code .

6

someone please help me out.
I am getting wrong answer for this solution

#include<stdio.h>
#include<string.h>

int main()
{
    int test = 0,hash_jew[150] = {0} ,count = 0;
    char c = 0;
    scanf("%d",&test);
    while(test--)
    {
        fflush(stdin);
        while(1)
        {
            scanf("%c",&c);
            if(c == '\n')
                break;
            hash_jew[c] = hash_jew[c]^1;
            count = count + hash_jew[c];
        }
        printf("%d\n",count);
        memset(hash_jew,0,sizeof(hash_jew));
        count = 0;
    }
    return 0;
}

When I used scanf("%s",c) as i/o then it got accepted.
Please tell me the difference between these two.

Accepted code:

#include<stdio.h>
#include<string.h>

int main()
{
    int test = 0, hash_jew[150] = {0}, count = 0, l, i;
    char c[1000];
    scanf("%d\n",&test);
    while(test--)
    {
        scanf("%s",c);
        l=strlen(c);
        for(i=0;i<l;i++)
        {
            hash_jew[c[i]] = hash_jew[c[i]]^1;
            count = count + hash_jew[c[i]];
        }
        printf("%d\n",count);
        memset(hash_jew,0,sizeof(int)*150);
        count = 0;
    }
    return 0;
}

Thanks in advance.

7

whats the problem with the following code???

http://www.codechef.com/viewsolution/1844213

8

@ritu2510 >> You are not supposed to print the “enter the number of test cases” thing here in the programs. There are testdata and your program is supposed to take input from standard input and give output on the standard output. It need not be “user friendly” in the output, it should just give correct output for each corresponding input.

UPD.

Moreover, you need not store all the input in an array and then display output at once. You should take an input and do the calculations and print the output and then take the next input and proceed in the same manner.
See, I modified your code: removed the “enter the number of test cases” thing and removed the array a[] into just a string a and it got Accepted. CodeChef: Practical coding for everyone

9

http://www.codechef.com/viewsolution/2058133
what is wrong with my solution?

10

Iam Getting wrong answer ,some might test cases might be missing pls suggest some typical test cases…

11

Can someone help identify bugs in my code? Or point me towards a few helpful test cases?

http://www.codechef.com/viewsolution/4663644

12

My code runs within time produces desired results uses the obvious login but still i am getting wrong answer!! please could someone help me with my following code:- CodeChef: Practical coding for everyone

13

This is getting a WA respose.


	use POSIX;
	$,=",";
	my $T=<>;
	chomp($T);
	while($T--){
		my $str=<>;
		chomp($str);
		my $ans=0;
		my %charCount;
    


			for(my $i=0;$i<length($str);$i++){
				$charCount{substr($str,$i,1)}++;
			}
			for(values %charCount){
				$ans+=ceil($_/2);
			}
		print $ans .  "\n";
	}

Can someone help with this.

14

#include<stdio.h>
#include<string.h>
int main()
{
int t,j,i,count;
char a[201];
scanf("%d",&t);
while(t–)
{
count = 0;
scanf("%s",a);
for(i=0;i<strlen(a)-1;i++)
{
if(a[i]!=’’)
{
for(j=i+1;j<strlen(a);j++)
{
if(a[i]==a[j])
{
a[i]=’’;
a[j]=’*’;
count++;
}
}
}
}
printf("%d\n",strlen(a)-count);
}
return 0;
}

what is wrong with this solutions works fine on my pc but gives wrong answer here. please help.

15

Why i’m getting wrong answer?
My code is
#include<stdio.h>
int check(int [],char);
int main()
{
int T,i,A[205]={0},cnt=0,x;
char ch[205];
scanf("%d",&T);
while(T–)
{ A[0]=-1;
cnt=0;
scanf("%s",ch);
for(i=0;ch[i]!=’\0’;i++)
{ x=check(A,ch[i]);
if(x)
{
cnt++;
}

        }
        for(i=0;A[i]!=-1;i++)
        {
            if(A[i]!=0)
            cnt++;
        }
        printf("%d",cnt);
}

return 0;
}

int check(int A[],char c)
{
int x,i;
for(i=0;A[i]!=-1;i++)
{
if(A[i]==c)
{
A[i]=0;
return 1;
}
}
A[i]=c;
A[i+1]=-1;
return 0;

}

16

I have tried my best to debug this code but can’t find the test cases am failing in , please correct my mistakes , it’s not very lengthy :

http://www.codechef.com/viewsolution/7301396

17

Can you tell me why this soln is wrong ?
It’s working perfectly fine in my m/c for all sorts of i/p
https://www.codechef.com/viewsolution/8339530

18

can u please tell my mistake in this code…
https://www.codechef.com/viewsolution/8534920

19

use someother value instead of “0” when u are marking, your loop is ending when its reaching any index where a[i]==0(0==NULL). -1 will work.

20

I have implemented the following solution. CodeChef: Practical coding for everyone

I am not sure in which test case it is failing… ? It worked for all the inputs provided in the Question. Can someone please point out the error in the logic.

21

Why is my answer coming wrong?CodeChef: Practical coding for everyone
Please help