PROBLEM LINKSDIFFICULTYMEDIUM PREREQUISITESSuffix Array, Longest Common Prefix Array PROBLEMGiven two strings a and b, let A be the set of all substrings of a, and B be the set of all substrings of b. Find the number of unique strings in A plus the number of unique strings in B, that are not common to both A and B. QUICK EXPLANATIONEfficient solutions to a large set of problems on strings are approachable by use of Suffix Arrays (or Trees). If you have not yet added Suffix Sorting (for construction of Suffix Arrays) to your skillset, then this is the perfect problem to do so. Suffix Sorting can be done using
Longest Common Prefixes of adjacent items in the list of sorted suffixes is a classical problem in strings. Most texts discuss construction of Suffix Arrays immediately followed by calculation of LCP arrays. The LCP Array can be found by augmenting the Suffix Sorting algorithms above. The time complexity for LCP Array calculation will be exactly equal to the time complexity of the Suffix Sorting. You can find it as an entirely different step as well, following the Suffix Sorting. Both O(L) and O(L log L) approaches will fit within the time limit for this problem. Hence, choose as you please :) Let us assume that we can find the number of unique substrings of a string by use of the LCP array for the suffixes of that string. (We will see the algorithm to do so in the EXPLANATION section) U(A) = number of unique strings in A We are given two strings a and b and their set of substrings A and B respectively. We wish to find U(A) + U(B)  U(A intersection B) Which is equal to U(A) + U(B)  (U(A union B)  U(A)  U(B)) Or 2*U(A) + 2*U(B)  U(A union B) EXPLANATIONLet us see how to find the number of unique substrings of a string by using the LCP array.
Let s be given string indexes in s are 1based Let S be the suffix array S stores the list of 1based indexes that represent the start position of the suffix of s Let L be the LCP array L(i) is the longest common prefix between the suffixes starting from S(i) and S(i1) Thus, L is only defined from 2 to s uniq_sub_strings = s  S[1] + 1 // thus we count all prefixes of the first suffix for i = 2 to N uniq_sub_strings += s  S[i] + 1  L[i] Let us try this with an example to see why this is correct. s = abaabba S = [ 7, // a 3, // aabba 1, // abaabba 4, // abba 6, // ba 2, // baabba 5 // bba ] L = [ 0, // not defined for L[1] 1, // a is the common prefix 1, // a 2, // ab 0, // nothing 2, // ba 1 // b ] uniq_sub_strings = 1 + 4 + 6 + 2 + 2 + 4 + 2 = 21 Thus, there are 21 substrings (out of 28) that are unique. You can work this out by deducing that the substrings that are not unique (and hence weren't counted are) { a, // prefix of aabba // since a was counted as prefix of "a" a, // prefix of abaabba a, // prefix of abba ab, // prefix of abba // since ab was counted as prefix of "abaabba" b, // prefix of baabba // since b was counted as prefix of "ba" ba, // prefix of baabba // since ba was counted as prefix of "ba" b // prefix of bba } Now, you can find U(A) and U(B) by using the above algorithm. The only part that remains is to calculate U(A union B). This can be done by considering a string c = a + "$" + b We can find all the unique substrings of c and reduce from the result, all the strings that contain the character '$'. We know that all the different strings that contain '$' are unique anyway, since '$' is not part of the alphabet. There are Thus, we can find U(A union B), the number of unique substrings that exists in either A, or B. We can find the number of unique substrings of either a, or b, but not both, in time O(F(a) + F(b) + F(a+b), where F(n) is the complexity of calculating the Suffix Array or the LCA Array (which ever is more). In the best implementation, F(n) = O(n). But the problem may be solved even with F(n) = O(n log n). SETTER'S SOLUTIONCan be found here. TESTER'S SOLUTIONCan be found here.
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asked 25 Mar '13, 00:16

Where can i read more about suffix array and LCP array? (algorithm and application) answered 25 Mar '13, 15:38
1
A very good pdf on suffix arrays for contest can be found here (http://www.stanford.edu/class/cs97si/suffixarray.pdf) Another source is http://emaxx.ru/algo/suffix_array but make sure you open it in Chrome.
(25 Mar '13, 18:08)
stanford link is not working!!!
(25 Mar '13, 21:19)
1
In the stanford link ')' is part of the hyperlink pasted here . Remove that and paste the link in your browser and you will able to access the pdf . Or use this link : http://www.stanford.edu/class/cs97si/suffixarray.pdf
(25 Mar '13, 21:21)

My first solution constructed the suffix array (in O(Nlog(N)) time) for each string independently (A, B and the union of A and B) and I got Time limit exceeded. I had to change my algorithm so that it computed everything only from the suffix array (and the LCPs) of the union of A and B. I thought that was intended, but now I see that I probably have some inefficiencies in my suffix array routines, which I will have to identify. answered 25 Mar '13, 00:44

does the solution that uses hashes exist ? answered 25 Mar '13, 00:51
Yes @acmonster construct LCP array using hashes in O(N log^2 N) time. We can compare two suffixes in O(log N) time using hashes. So we can sort them in O(N log^2 N) time. And then calculate LCP array in O(N log N) time.
(25 Mar '13, 01:10)

http://www.codechef.com/viewsolution/1966634 My solution works on all test cases i found but still gives runtime error please help answered 26 Mar '13, 18:29

@anton_lunyov sir may u plzz provide me the test cases where this solution is failed http://www.codechef.com/viewsolution/1967060 thanx in advance..:) answered 27 Mar '13, 00:19
3
Try large test where both strings have equal characters.
(27 Mar '13, 00:46)
thank you sir..:) accepted..
(27 Mar '13, 00:58)

Can someone help me with the stdin and stdout for node.js. My code is as follows
process.stdin.setEncoding('utf8'); process.stdin.on('data', function (chunk) { var lines = chunk.toString().split('n');
}); answered 27 Mar '13, 23:44

@anton sir would you please tell me where is my code failing here's my code :( answered 28 Mar '13, 23:38

@anton_lunyov : sir please help me every time i get a run time error(SIGSEGV)... answered 29 Mar '13, 07:56

hello, could you just tell me weather my code's output is correct or not, irrespective of time exceed error.. answered 29 Mar '13, 12:54

why doesnt work?
answered 31 Mar '13, 08:24

getting run time error NZEC. first submission in codechef. so dont know much abt online compilers. plz help me out sir http://www.codechef.com/viewsolution/5666193 answered 29 Dec '14, 14:01
First try to comment
(29 Dec '14, 15:14)
I'd say, that problem is with memory, you want to allocate array of strings of length n^2 (and n is 100000).
(29 Dec '14, 15:22)
array of strings with no of strings is n2, where n2 being 10 for a four letter word 10=4+3+2+1 so n2=no of letters +(no of letters1)+.....+ 1
(01 Jan '15, 13:57)
and sir system.exit(0) presence or absence has no effect in this case in the runtime error.. any other suggestions sir ? thanks
(01 Jan '15, 13:58)

Wow.. that was a quite a sleek approach... Nice one answered 16 Jan '15, 20:23

This problem really showed our "level" :)
I did the same thing as the tester . My solutions (during the contest[http://www.codechef.com/viewsolution/1964089]) and after the contest with some optimizations (http://www.codechef.com/viewsolution/1964221) both TLE .. Is this too strict for Java ? EDIT: I think he has a better Suffix array function.