Can Somebody help me about what's wrong with my solution for JULY challenge problem chef and tetris and my approach was to check out 4 possible values so that we can make all array elements equal but I am getting wrong answer for 7th and 12th task my solution : https://www.codechef.com/viewsolution/10812639 asked 15 Jul '16, 07:54

@sau1999 I tried running your code on my PC, for this particular input: answered 15 Jul '16, 14:00
@hemanth_1 : thanks for giving answer but i think for your given test case answer should be 3 because b = {1,2,3} a = {1,2,3} b[1] will fall on a[0] (2 + 1 = 3) b[0] will fall on a[1] (1 + 2 = 3) and as a[2] is already 3 no element will on a[2] thus vis[n1] = 0`
(15 Jul '16, 15:00)
@sau1999 Where shall b[2] fall?
(15 Jul '16, 15:11)
All the elements in 'B' must be used
(15 Jul '16, 18:32)
thanks for clearing the problem statement I asked this question on the contest but no one replied
(15 Jul '16, 19:02)

This happened with me as well. It is happening because of n=1. Just a separate if statement for n=1 needs to be added. answered 15 Jul '16, 15:52

can you tell me what is wrong in my solution for chef and tetris. https://www.codechef.com/viewsolution/10824494 my approach is somewhat similar to you. i also try to make all element equal to a[0] or a[0]+b[0] or a[0]+b[1] or a[0]+b[0]+b[1]. i try to go through your code what its hard to get what you are trying to do. one funny thing is that your solution is not passing the 7th and 12th task and my solution is failing on 1st task. answered 15 Jul '16, 13:54

@hemanth_1 please tell me why my solution is wrong. https://www.codechef.com/viewsolution/10824494 answered 15 Jul '16, 14:43

Please tell me what's wrong with this : https://www.codechef.com/viewsolution/10763381 Thanks in advance. answered 15 Jul '16, 22:20

Can anyone please tell me whats wrong in my code answered 17 Jul '16, 17:03

Hey.. in this problem i got stuck in the 10th test case.. can any one tell whats wrong with my approach?? my algo is: if all elements of (a[n]+b[n]) is not divisible by n> then print 1 else check for all the possible sums for one a[i] { b[i1]+a[i] , b[i]+a[i] , b[i+1]+a[i] , b[i1]+b[i]+a[i] , b[i+1]+b[i]+a[i] ,b[i1]+b[i+1]+a[i] and b[i1]+b[i]+b[i+1]+a[i]} from these if a[i]+any of these are equal to the desired element that is (a[n]+b[n])/n then making the/those b[i] value/values zero i proceed to check next a[i] element. here is the source code.. https://www.codechef.com/viewsolution/10759208 answered 17 Jul '16, 21:25
