Please explain how merge sort work and calculate the time complexity of merge sort. asked 10 Nov '16, 22:58

Merge sort can be precisely described by a tree of height = ( log2(n) + 1 ) for an array of size n. Consider the diagram. If we manage to ensure the work done at each level of the tree is O(n) then the total work would be of the order n*(height of the tree). So that would be O(nlog(n)). This is where the merge subroutine comes into the picture.The argument we make is that work done to merge to sorted arrays is O(n). And hence at each level total work = (total subproblems)*(work for each subproblem).If we assume the above statement to be true. I wont go into the details of merge subroutine.But subproblems at each level = 2^(level) if root is at level 0. Work to solve a subproblem = size of subprobem = n/2^(level) Total work at each level = (2^(level)) * (n/2^(level)) = n Total work in all levels = Total work at each level * (Total number of levels) = n*( log2(n) + 1 ) = O(nlogn) answered 10 Jun '17, 23:39

can you please explain me how to create a call recording app like this answered 11 Nov '16, 00:56

The University of Seville (US) continues to climb positions Mathway  Problem Solver in the QS ranking, something that is reflected in the data of the latest report of the QS World University Rankings 2017 by subject, where the Seville is located among the 500 best universities in the world in 19 disciplines, occupying four of them put in the range 151200. answered 10 Jun '17, 12:52

As far as complexity is concerned, it's NlogN in all cases. answered 10 Jun '17, 17:02
