How to implement LIS(Longest Increasing Subsequence) using recursion and top down dp efficiently?
There you go : algorithm - Does there exist a Top Down Dynamic Programming solution for Longest Increasing Subsequence? - Stack Overflow
Dear @rashedcs
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And here’s a problem and it’s successful submition
Problem link:- The Longest Increasing Subsequence | HackerRank
#include <iostream>
#include <string.h>
#include <stdio.h>
using namespace std;
#define ARRAY_SIZE(A) sizeof(A)/sizeof(A[0])
// Binary search (note boundaries in the caller)
// A[] is ceilIndex in the caller
int CeilIndex(int A[], int l, int r, int key) {
int m;
while( r - l > 1 ) {
m = l + (r - l)/2;
(A[m] >= key ? r : l) = m; // ternary expression returns an l-value
}
return r;
}
int LongestIncreasingSubsequenceLength(int A[], int size) {
// Add boundary case, when array size is one
int *tailTable = new int[size];
int len; // always points empty slot
memset(tailTable, 0, sizeof(tailTable[0])*size);
tailTable[0] = A[0];
len = 1;
for( int i = 1; i < size; i++ ) {
if( A[i] < tailTable[0] )
// new smallest value
tailTable[0] = A[i];
else if( A[i] > tailTable[len-1] )
// A[i] wants to extend largest subsequence
tailTable[len++] = A[i];
else
// A[i] wants to be current end candidate of an existing subsequence
// It will replace ceil value in tailTable
tailTable[CeilIndex(tailTable, -1, len-1, A[i])] = A[i];
}
delete[] tailTable;
return len;
}
int A[1000009]={0};
int main() {
int n,i;
cin>>n;
for(i=0;i<n;i++)
cin>>A[i];
printf("%d\n",LongestIncreasingSubsequenceLength(A, n));
return 0;
}
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