×

Easy-Medium

Binary Search

# Problem:

Find the maximum number x for which the sum of x natural numbers don't exceeds the litres of water available.

# Explanation:

Given that the first bucket has a capacity of 1 litre, second bucket has capacity of 2 litres and so on. So we just need the maximum number x so that $1+2+3+....+x <=n$, where n is the litres of the water available. Thus, problem is a searching problem, we are just searching for the required x.

First approach is we can use linear search to find the value of x but it will exceed the time limit. So, we have to think of a more efficient searching approach.

Next approach is to use the binary search as it is very efficient and very well within the time limit of the problem.

# Solution:

Author's solution can be found here.

161
accept rate: 0%

19.0k348495531

 0 testcases=int(input()) while (testcases!=0): test=int(input()) #print(test) sum=count=0 for i in range(1,test+1): if sum < test : sum+=i count+=1 else: break print(count) testcases-=1 answered 11 May '17, 11:09 1 accept rate: 0%
 0 Why can't we just use the formula for Sum of first n natural numbers? (n*(n+1))/2 = N This was mine, I don't know why I was getting TLE. I mean, I'm okay with getting a wrong answer (I just re-read the question and saw the line, "The bucket will be considered filled if it has atleast 1 litre in it.") But why am I getting a TLE? Is the sqrt() function that heavy/slow? answered 11 May '17, 11:27 41●2 accept rate: 0% It is because the problem is not that easy. The time limit of the problem is very less. So you can't use the linear approach. The problem was designed that way. (12 May '17, 14:35)
 0 import math for t in range(input()): s=int(raw_input()) a=1 b=1 c=-2s d=b2-4ac if d>0: x1=-b+math.sqrt(d) x1=x1/2a print int(math.ceil(x1)) answered 11 May '17, 15:40 2★srvshrm 1 accept rate: 0%
 0 I based my solution on this editorial but I got a WA response. Can someone point out the mistake in my code. And I am trying to understand the approach used in the following solutions... singh_8 and sayan009 but cant get it... answered 20 May '17, 09:15 31●2 accept rate: 0%
 0 @goof_expert Hi. See in line 22, you should be checking for <=N (you did
 0 I used the formula for sum of first n natural numbers and got a WA, but a simple linear approach for summing up the first n natural numbers gave AC, instead of TLE. answered 28 Feb, 19:18 1 accept rate: 0%
 0 I m very pleased to discover this page. I want to thank you for your time just for this wonderful read !! I definitely loved every little bit of it and I have you bookmarked to check out new things on your blog.And new code on programming that you shared with us in future.Essay Writing Service very thankful to you for this post. answered 02 Mar, 11:33 1 accept rate: 0%
 0 You can use the formula (n*(n+1))/2=N and convert them into a quadratic equation to solve the problem. You can check my solution for this problem link text Here i use sheree dharacharya formula to find the solution. And it accepted in one go. answered 03 Mar, 11:53 25●2 accept rate: 0%
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question asked: 11 May '17, 08:24

question was seen: 995 times

last updated: 09 Mar, 12:34