I am trying to solve Bon appetit problem from Jan challenge 2014 from 6 days.Still couldn't solve it out.. So it would be really nice if someone could help me to solve out this. I am trying to solve it in the following way.
1.Sort customers according to departure time.(quicksort)
2.Then go through each customer and directly retrieve a recent customer in that compartment.
if it results in an overlap(discard the customer).
else
increment count and update the recent customer in the specified compartment.
I came to know that a hashmap would serve the purpose.Each compartment would be mappped to certain index by the hashing function and then we would directly go there.
Questions.
1.How can i build a hash function so that given a compartment it would map it to certain index and when again a customer of this compartment appears i would directly go to this compartment in 1 operation.
2.Would this approach give me WA or TLE?
Please ~~help....~~help...