My solution is getting WA for Sub-task 2, Task#4, can anyone suggest any edits?
t = int(input())
for i in range(t):
x, y, k, n = map(int, input().split())
l = [0]*n
cost = [1000]*n
j=0
for j in range(n):
l = list(map(int, input().split()))
if l[0]>=(x-y):
cost[j] = l[1]
if min(cost)<=k:
print("LuckyChef")
else:
print("UnluckyChef")
When I am running my code on ideone compiler ,the output is coming correct.But on running through it shows wrong answer.Can someone explain how to do subtasks?I made variable N and T long int still my answer is not getting accepted
How to solve it, if we are allowed to buy multiple notebooks instead of just one? Do we need to need to use Knapsack DP?
package easyLevel;
import java.util.Scanner;
public class ChefNNotebooks_CNOTE {
public static void main(String args[]){
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
while(T > 0){
String result = "UnluckyChef";
int X = sc.nextInt();
int Y = sc.nextInt();
int K = sc.nextInt();
int N = sc.nextInt();
while(N > 0){
int P = sc.nextInt();
int C = sc.nextInt();
if(C <= K && P >= X-Y){
result = "LuckyChef";
break;
}
N--;
}
System.out.println(result);
T--;
}
}
}
gettinh WA, not sure why
After the implementaion on C++ code, in the statement "Note that we used ‘\n’ instead of endl, because endl forces a flush, " what is flush and when can we know flush occured in the program (or) not?
Love your approach, multiple examples in multiple language !!!
There is a problem because you broke out of the loop too early while reading N pairs of integers (Pi, Ci). This means that the next Pi will be interpreted as the X of the next case, the Ci will be interpreted as the Y, and so on. Or if you are processing the input line by line, then you might get runtime error, because you were expecting four integers (X, Y, K, N) but only got two (Pi, Ci).
The explanation has been updated to explain this.
@saiavinashiitr a link explaining “flush” has been added. The idea is that when you do cout << something, the something isn’t necessarily immediately printed to the console/stdout. cout usually buffers them first, and then prints by batch, because printing something to the console is slow.
You call “flush” when you want it to be printed immediately (just like flushing a toilet). However, endl always forces a flush, causing unnecessary overhead in printing. By using '\n', there is no flush, so it’s faster.
@kevinsogo : Thank you, and your way of pointing out the common mistakes is nice and overall u made this editorial awesome 
Now I get it. Thanks !
Here’s a more pythonic code golf:
for _ in xrange(input()):
X, Y, K, N = map(int, raw_input().split())
print ["UnluckyChef", "LuckyChef"][any(P >= X - Y and C <= K for P, C in [map(int, raw_input().strip().split()) for i in xrange(N)])]When you post code, you should try indenting all your code four spaces, so that it renders properly as code.
because you are breaking the loop after getting result. you are not collecting all the input data. hence getting the wrong answer. remove break statement and you would get the correct answer.
i get a wrong answer when i use this snippet to take an integer input
int fastscan()
{
int c = gc();
int x = 0;
for (; (c>47 && c<58); c=gc())
x = x *10 + c - 48;
return x;
}
but when i used cin instead of this snippet my solution gets accepted.
@kevinsogo
Total number of test cases =10^5
Total Iterations in subtask1=10^9
subtask2=10^11
But we are allowed only 10^8 iterations , so how this code is running, can anyone help??
thanks for the message this helped me a lot,kudos!
Following is my CPP code. what am I doing wrong?
Not even first subtask is correct.
#include <iostream>
using namespace std;
int main() {
int t, x, y, k, n, pi, ci;
bool found;
cin >> t;
while(t--){
cin >> x >> y >> k >> n;
found = (y >= x) ? true: false; // current book is enough.
while((n--) && (!found)){
cin >> pi >> ci;
if((ci <= k) && (pi >= (x - y))){
found = true;
}
}
if(found)
cout << "LuckyChef" << endl;
else
cout << "UnluckyChef" << endl;
}
return 0;
}
#include <iostream>
using namespace std;
int main() {
int t, x, y, k, n, pi, ci;
bool found;
cin >> t;
while(t--){
cin >> x >> y >> k >> n;
found = (y >= x) ? true: false; // current book is enough.
while((n--) && (!found)){
cin >> pi >> ci;
if((ci <= k) && (pi >= (x - y))){
found = true;
}
}
if(found)
cout << "LuckyChef" << endl;
else
cout << "UnluckyChef" << endl;
}
return 0;
}#include <iostream>
using namespace std;
int main() {
int T;
cin>>T;
for(int i = 0; i < T; i++){
int X,Y,K,N;
cin >> X >> Y >> K >> N;
bool luck = false;
for(int j =0; j < K;j++){
int p,q;
cin>>p>>q;
if(q <= K & p >= (X-Y)){
luck = true;
}
}
if(!luck){
cout<<"UnluckyChef"<<' ';
}else{
cout<<"LuckyChef"<<' ';
}
}
return 0;
}
i cant understand whats wrong with this code.
#include <stdio.h>
int main(void) {
// your code goes here
int i,j,k,l;
int nooftestcases;
scanf("%d",&nooftestcases);
for(i=0;i<nooftestcases;i++){
int storypages,existingpages,pagesrequired,moneyleft,noofbooks;
scanf("%d",&storypages);
scanf("%d",&existingpages);
//printf("%d\n",pagesrequired);
scanf("%d",&moneyleft);
scanf("%d",&noofbooks);
//pagesrequired = storypages - existingpages;
//printf("%d\t%d",moneyleft,noofbooks);
for(j=0;j<noofbooks;j++){
int bookpages,cost;
scanf("%d",&bookpages);
scanf("%d",&cost);
if(bookpages>=storypages - existingpages && moneyleft>=cost){
printf(“LuckyChef\n”);
break;
}
bookpages;cost;
}
if(j==noofbooks){
printf(“UnluckyChef\n”);
}
}
return 0;
}
can someone pls look into the code and tell what’s wrong
#include <iostream>
using namespace std;
int main(int argc, char *arg[]) {
long int T, X, Y, K, N;
cin >> T;
long int t = 0, n, pi, ci, req_pages;
bool found;
while (t < T) {
cin >> X >> Y >> K >> N;
req_pages = X-Y;
n = 0;
found = false;
while (n < N) {
cin >> pi >> ci;
if ((req_pages <= pi) && (ci <= K)) {
found = true;
break;
}
++n;
}
cout << (found ? "LuckyChef" : "UnluckyChef") << '\n';
++t;
}
return 0;
}
I don’t see anything wrong with the program and yet I’m unable to get the right …