x = a ^ b, a < b,
lets k is msb bit of a,
now x > max(a, b) iff kth bit of b is 0.
for each Ai , kth bit of Ai is 0, then we have to count Aj such that k is msb bit of Aj.
x = a ^ b, a < b,
lets k is msb bit of a,
now x > max(a, b) iff kth bit of b is 0.
for each Ai , kth bit of Ai is 0, then we have to count Aj such that k is msb bit of Aj.
Line #7 for j in range(x):
you need to use
for j in range(i, x):
If it still doesn’t work then sort the list then use
if (arr[i] ^ arr[j]) > arr[j]: count += 1
Got it. Thanks
getting wrong answer and no one is successful solution in python.
check here => CodeChef: Practical coding for everyone
#include
#include <bits/stdc++.h>
using namespace std;
int main()
{ ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
unsigned int t,n=0,count=0;
unsigned c=0;
cin>>t;
while(t–)
{
cin>>n;
vector v(n,0);
for(int i=0;i<n;i++)
cin>>v[i];
sort(v.begin(),v.end());
for(int i=0;i<n-1;i++)
{
for(int j=i+1;j<n;j++)
{
c=v[i]^v[j];
if(c>v[j])
{
// if(c>v[j])
++count;
}
}
}
cout<<count<<"\n";
count=0;
// c=0;
}
// your code goes here
return 0;
}
I have fixed the code, if any questions about it ask me
` #include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t, n=0, count=0; // Changed from unsigned int to int, No need to do it, just did it for debugging sakes.
unsigned c=0;
cin >> t;
while(t--) {
int n; // Never initialized n
cin >> n;
vector <int> v; // Wrong method of initialization of a vector, fixed it.
for(int i=0;i<n;i++) { // You were missing braces here
int inp;
cin >> inp;
v.push_back(inp);// cin>>v[i]; This method is used for arrays, use the corrected one for vectors; It will add a element at the end of the vector.
}
sort(v.begin(),v.end());
for(int i=0;i<n-1;i++) {
for(int j=i+1;j<n;j++) {
c = v[i] ^ v[j];
if(c > v[j]) count ++;
}
}
cout << count << "\n";
count = 0;
}
return 0;
}
i had the similar approach got
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int main()
{
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
ll t;
cin>>t;
while(t--)
{
ll n;
cin>>n;
ll arr[n];
for(ll i=0;i<n;i++)
cin>>arr[i];
ll X,cnt=0;
for(ll i=0;i<n;i++)
{
for(ll j=i;j<n;j++)
{
X = arr[i]^arr[j];
if( X>arr[i] && X>arr[j])
cnt++;
}
}
cout<<cnt<<endl;
}
return 0;
}
Thanks buddy, you just did wonderful work…
Bhagwam aapko arabpati bnaaye😁
Thanks Ashish