1 ≤ N,M ≤ 10^{18}

code using Fast Doubling

#include #include #include using namespace std; #define MAXN 60 #define MAXM 4 long long int M,N ; long long F[MAXN][MAXM],FB[MAXN+5]; void readint(long long &a) { register int c; a = 0; do c = getchar_unlocked(); while(c < '0'); do{ a = (a << 1) + (a <= '0'); } void printint(long long int a) { char s[21]; int t = -1; do{ s[++t] = a % 10 + '0'; a /= 10; }while(a > 0); while(t >= 0)putchar_unlocked(s[t--]); putchar_unlocked(' '); } long long int mulmod(long long int a,long long int b) { long double res = a; res *= b; long long int c = (long long)(res / M); a *= b; a -= c * M; a %= M; if (a < 0) a += M; return a; } long long int f(long long int n,int depth = 0 ) { if(n<=MAXN){ return FB[n]%M ; } int val = n%4 ; if (F[depth][val] != -1) return F[depth][val]; long long int k=n >> 1; long long int a,b,c; a = f(k,depth+1) ; b = f(k-1,depth+1) ; if (n%2==0) { F[depth][val] = (mulmod(a,a) + mulmod(b,b)); }else { c = f(k+1,depth+1) ; F[depth][val] = (mulmod(a,c) + mulmod(b,a)); } if(F[depth][val] >= M) F[depth][val] -= M ; return F[depth][val] ; } int main(){ int T = 63450 ; FB[0] = 1 ; FB[1] = 1 ; for(int i=2;i<=64;i++){ FB* = FB[i-1] + FB[i-2] ; } while(T--){ memset(F,-1,sizeof F) ; readint(N) ; readint(M) ; printint((N==0 ? 0 : f(N-1))) ; } return 0 ; }