FIBEASY - Editorial

Check cp-algorithms.com it’s a good starting point

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this is link to my solution CodeChef: Practical coding for everyone i used the logic that unit digit of fibonacci repeats after 60 digits and the selected element in array can be represented as a[2^n-1].
please tell me if code could be improved in some way

i also think the same, i think apart from the solution , its more challenging for a beginner to understand what mathematical concepts have been used , the editorial maker directly uses the various maths concept and make it harder , for beginners like me to understand .

so i think they should , go with more simpler approach to explain the logic.

another alternative is to use log2l instead of log2
It worked for me

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Receiving RE for the third input. I have tried so many approaches but still issue persists.


import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		int t;
		int f[] = {0,1,1,2,3,5,8,3,1,4,5,9,4,3,7,0,7,7,4,1,5,6,1,7,8,5,3,8,1,9,0,9,9,8,7,5,2,7,9,6,5,1,6,7,3,0,3,3,6,9,5,4,9,3,2,5,7,2,9,1};
		Scanner in = new Scanner(System.in);
		t = in.nextInt();
		while(t>0)
		{
		    long n,i;
		    i = 1;
		    n = in.nextInt();
		    while(i<=n)
		    {
		        i = i*2;
		    }
		    i = i/2;
		    i=(i-1)%60;
		System.out.println(f[(int)i]);
		t--;
		}
	}```
Is there any way we can find where im getting RE?

Please format your code - the forum software has mangled it and it is no longer valid Java! :slight_smile:

Edit:

Try the testcase

1
576460752303423487
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Thanks, prblem is with the way Im reading the input. changed “nextInt()” to “nextLong()” and it worked fine.

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This will help you alot : Easy Fibonacci | September long challenge 2019 | Codechef Solutions & Code || FIBEASY | Hello World - YouTube
see this thank you

this will help you a lot :
Just Go through This

Please Subscribe my channel Hello World .

3 Likes

where am i going wrong?

arr =[0,1]
for x in range(60-2):
arr.append((arr[-1]+arr[-2])%10)

def red(arr,n):
brr = arr[:n]
while(len(brr)!=1):
brr = brr[1::2]
return brr[0]

tc = int(input())
for i in range(tc):
num = int(input())
print(red(arr,num%60))

plss tell me where its exceeding time limit

Can someone point out the error in my code?

import java.util.*;
class Fibnocci {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int t,n,ans;
		ArrayList<Integer>a = new ArrayList<Integer>();
		ArrayList<Integer>e = new ArrayList<Integer>();
		Scanner sc = new Scanner(System.in);
		t = sc.nextInt();
		while(t>0){
			n = sc.nextInt();
			a.add(0);
			a.add(1);
			for(int i=2;i<n;i++){
				a.add(a.get(i-1)+a.get(i-2));
			}
			for(int i=0;i<n;i++){
				a.set(i, a.get(i)%10);
			}
			if(a.get(a.size()-1)==1){
				while(a.size()>1){
					for(int i=0;i<a.size();i++){
						
							if(i%2==0){
								a.set(i,-1);
							}
					}
					for(int i=0;i<a.size();i++){
						if(a.get(i)==-1){
							a.remove(i);
						}
					}
				}	
			}		
			ans=a.get(0);
			System.out.println(ans);
			t--;
		}
	}
}

For people who need more clear explanation of the editorial can go to the GitHub link: Easy Fibonacci

can anyone check why i am getting wrong answer on this::
double n = in.readDouble();
int x = (int)(Math.log(n) /
Math.log(2));
x = (int)Math.pow(2, x);
out.printLine(fib(x-1)%10);
out.flush();
//fib(x-1) is implemented in logn using matrix expo

@as_max_rider You can check your program output for the following test-cases:
4
9
72057594037927935
72057594037927936
18014398509481983

Output shoud be:
3
3
0
9

If your program is not giving the correct answer then read the editorial: Easy Fibonacci
Probably there is problem with how you are calculating log. Does your log function gives correct answers for large values.

NOTE: You don’t need to use matrix exponentiation.
You can also read the following post: FIBEASY Matrix Exponentiation Solution? O(lgn) (edit: this solution failed for subcase 3 Yet I am producing right answers?) - #3 by striker22

you were right!!
my problem was with the log function.
my idea was almost same as the editorial except i didn’t use the periodicity part…
i observed a relation among the numbers

1 Like

@as_max_rider Well its good that you figure it out. :slight_smile:

hey everyone. cant i avoid TLE using this method i have done?

https://www.codechef.com/viewsolution/27348754

Hi,

I am seriously facing trouble understanding that. Can anybody give me an easy explanation.

Or handily you can avoid any sort of log function - use the bit_length() function of int class.

1 Like