https://www.codechef.com/viewsolution/37287056
solution link
The below solution is accepted and it is easy to understand .
https://www.codechef.com/viewsolution/37279799
ok thanks for this
but can you tell me the problem in my solution
1
5
1 1 1 1 1
Try this
mine giving 5
its right, wait i’ll generate random test and we’ll figure it out
7
7 1 2 1 2 1 2 1
10 1 10 9 9 10 7 7 3 3 31
1 5
6 2 2 2 2 2 2
6 1 1 2 2 3 3
9 1 2 3 4 5 6 7 8 9
12 10 10 12 12 1 1 1 1 20 20 19 18
output
3
2
1
6
2
1
2
its fine here too
but for the first round output should be 1
7 => 1
1=> 4
2=> 3
1
5 1 1 1 1 2
try this
1 Like
7 is n, bruh
I told you because this method is used frequently and may be in some different question, chances are high that you may get tle. You can’t be lucky every time 
1 2 1 2 try this
Can someone help me with my code as well. Where have I gone wrong? My guess is maybe in the for loop but I can’t figure it out.
https://www.codechef.com/viewsolution/37290671
bruh i think u missed braces in if else
what does counter do
Counter counts the occurrence (frequency) of each elements in the list and returns a dictionary of {elems:frequencies}
instead of val = list(map(int, numval.split())), u gave val = list(map(int, input().split()))
Also correct ur code
1
12
10 10 12 12 1 1 1 1 20 20 19 18
o/p: 2
ur o/p: 1