Don’t Use new line after displaying the answer.
My Code :-
#include< iostream>
#include< iomanip>
using namespace std;
int main(void)
{
float y,z;int x;
cin>>x>>y;
cout<< fixed<< setprecision(2);
if(x>0 && x<=2000 && y>=0 && y<=2000){
if(x>=y)
cout<< y;
else if(x<=y-0.5)
{
if(x%5==0)
cout<< y-x-0.50;
else
cout<< y;
}
else cout<< y;
}
return 0;
}
Enjoy bro
import java.util.Scanner;
import java.text.DecimalFormat;
public class Main
{
public static void main(String args[])
{
double withdraw,balance;
Scanner sc=new Scanner(System.in);
withdraw=sc.nextDouble();
balance=sc.nextDouble();
if((withdraw%5==0) && (balance>=(withdraw+0.05f)))
System.out.println(new DecimalFormat(“0.00”).format(balance-withdraw-0.05f));
else
System.out.println(new DecimalFormat(“0.00”).format(balance));
}
}
#include<stdio.h>
float a,b,c;
int mul(float n);
int main(){
scanf("%f %f",&a,&b);
if(a<=b){
if(mul(a)){
c = b - a - 0.5;
printf("%.2f",c);
}
}
if(!mul(a))
printf("%.2f",b);
if(a>b)
printf("%.2f",b);
}
int mul(float n){
while(n>0.0)
n=n-5.0;
if(n==0.0)
return 1;
else
return 0;
}
can anyone tell, why it is showing wrong answer
What is wrong in this code of mine ?
#include <iomanip>
#include <iostream>
int main()
{
int x;
float y;
std::cin >> x >> y;
if ((x % 5 == 0) && (x + 0.50 <= y))
{
if (0 < x && x <= 2000 && 0 <= y && y <= 2000)
{
float j = y - x - 0.50;
std::cout << std::setprecision(2) << std::fixed << j;
}
}
else
{
std::cout << std::setprecision(2) << std::fixed << y;
}
return 0;
}#include
#include
using namespace std;
int main(){
int witha;
float balanb;
cin >> witha;
cin >> balanb;
if (witha< balanb){
if(witha%5==0){
balanb= balanb-witha-0.5;
cout << balanb;
}
else {
cout<< balanb;
}
}
else{
cout << balanb;
}
return 0;
}
Whats the error??
How to start with the python. I am begining to the python but i am getting error? so Kindly reply me.
#include <stdio.h>
#include <stdlib.h>
int main() { int a=0; float
b=0;
scanf("%d %f",&a,&b);
if(a<b){
if(a%5==0){
printf("%.2f\n",(b-a)-0.50);
}
else{
printf("%.2f\n",b);
} } else{
printf("%.2f\n",b);
}
return 0; }
Why is wrong ?
#include
#include
#include<stdlib.h>
using namespace std;
int main()
{
int withdrw;
float max_bal,bal;
cin>>withdrw;
cin>>max_bal;
if((withdrw>0)&&(withdrw<2000)){
if((max_bal>0)&&(max_bal<2000))
{
if(withdrw<max_bal)
{
if(withdrw%5==0){
bal=max_bal-withdrw;
bal=bal-0.50;
cout<<setprecision(2)<<fixed<<bal;
}
else
{
bal=max_bal;
cout<<setprecision(2)<<fixed<<bal;
}
}
else
{
bal=max_bal;
cout<<setprecision(2)<<fixed<<bal;
}
}
}
else
{
exit(0);
}
return 0;
}
what is the problem in this code
#include<stdio.h>
main()
{
int a;
float b;
scanf("%d",&a);
scanf("%f",&b);
if(a>0 && a<=2000 && b>0 && b<=2000)
{
if(a%5==0)
{
if( b>=(a+.50))
{
b=b-a-0.5;
printf("%0.2f",b);
}
if(b< a+.5)
printf("%0.2f",b);
}
else
printf("%0.2f",b);
}
}
What is wrong with this code?
#include<stdio.h>
int main(){
unsigned int amt;
float atm=0.5,bal,rlt;
scanf("%u %f",&amt,&bal);
if((bal+atm)>=amt && amt%5==0 && (0<=bal<=2000) && (0<amt<=2000))
rlt=bal-(amt+atm);
printf("\n%.2f",rlt);
return 0;
}
whats wrong in my code
amnt ,bal = [float(x) for x in input().split()]
print(bal,amnt)
if(amnt > 0 and bal > 0):
if(amnt <= 2000.00 and bal <= 2000.00):
if(amnt+0.5 <= bal and amnt%5 == 0 ):
print(format(bal-amnt-0.50,".2f"))
else:
print(format(bal,".2f"))
whats wrong in this
#include <stdio.h>
#include <stdlib.h>
int main()
{
int transaction;
double balance, response, charges;
balance=2000;
charges=0.50;
printf("\n ATM Machine");
printf("\n------------------");
printf("\n1 Enter the Saving Account");
printf("\n2 Enter the Withdraw money");
printf("\n3 Quit");
printf("\nEnter your Selection:");
scanf("%lf", &response);
if(response==1)
{
printf("\n---------------------");
printf("\nYour current balance: %0.2lf", balance);
printf("\n---------------------");
printf("\nThank you\n");
}
if(response==2)
{
printf("\nEnter amount to withdraw:");
scanf("%d", &transaction);
if((transaction)%5==0)
{
printf("\n---------------------");
printf("\nYour current balance: %0.2lf", balance-transaction-charges);
printf("\n---------------------");
printf("\nThank you for Transaction\n");
}
else
{
printf("\nTransaction Failed");
}
}
if(response==3)
{
printf("\nThank you\n");
}
return 0;
}
Brother, check this code. And tell me what’s wrong on it.
#include <stdio.h>
int main(){
unsigned int amount;
float balance;
scanf ("%d %f",&amount,&balance);
if (balance>=0 && balance <=2000){
if (amount<=(balance-0.5) && amount>0){
if(amount%5==0)
printf("%f",(balance-amount)-0.5);
}
}
return 0;
}
what is the error here? please help me
import java.util.Scanner;
import java.text.DecimalFormat;
class Atm{
public static void main(String[] args){
Scanner s=new Scanner(System.in);
System.out.println("enter amt to be withdrawn:");
double a=s.nextDouble();
System.out.println("enter the current amount in account");
double b=s.nextDouble();
DecimalFormat df=new DecimalFormat("#### 0.00");
if((0<a)&&(0<b)){
if((a<=2000.00)&&(b<=2000.00)){
if(a>b)
System.out.println(df.format(b));
if((a%5)!=0)
System.out.println(df.format(b));
if(((a%5)==0)&&(a==b))
System.out.println(df.format(b-a));
if(((a%5)==0)&&(a<b))
System.out.println(df.format((b-a)-0.50));
}
}
}
}
How to get input in python? Example for python here in forum doesn’t work like:
wd_amt,in_amt = list(map(float, input().split()))Editorialist solution is wrong withdraw%5==0&&balance>=withdraw+0.5 is the correct condition…
You dont need those printf() statements you have added in your code. There’s no need of that, go by the I/O format specified in the problem!!
Suppose the input is 120 120.00 then your code gives the output -0.50. Check for that case also. Answer for this case should be 120.00
do paste your code with proper identation.
if((x%5==0)&&(x<y))-This is faulty, as y should be greater than x+0.5, as problem clearly says "enough cash to perform the withdrawal transaction (including bank charges). "
Make changes and get back to me in case of discrepancy 