We are assuming n \equiv i\ mod\ p-1 and calculating the answer. So yes a^n \equiv a^i\ mod\ p
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Thanks a lot. You made my day 
. The difficulty lies in assumption.
We are assuming n \equiv i\ mod\ p-1 and calculating the answer. So yes a^n \equiv a^i\ mod\ p
Thanks a lot. You made my day . The difficulty lies in assumption.