#ifndef ONLINE_JUDGE ?

general
,
1

GOOGLED IT YET COULDNT FIND ANTHING


inline void debugMode() {

#ifndef ONLINE_JUDGE

freopen("input.txt", "r", stdin);

freopen("output.txt", "w", stdout);

#endif // ONLINE_JUDGE

}


i was solving a problem on codeforces, though i couldn’t do so… so i tried looking at someone else’s code and found this. As being a newbie couldn’t get why are we looking for if ONLINE_JUGES CONSTANT is set, if not opening a file in read mode… are we taking all inputs in one go to fasten process?? can anyone be a bit descriptive to this as i have already looked at codechef and stackoverflow and codeforces links explaining this…

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This is a general practice by c++ programmers who code in a text editor rather than an IDE. By default the ONLINE_JUDGE constant is defined when submitting code in most online judges like Codechef and Codeforces. Thus it provides a way for the code to determine whether the code is being run in an online judge or a local machine, where the constant is not defined in the latter. Generally this flag is used in order for the code to read & write from a file rather than stdin when run on a local machine and read & write from stdin and stdout respectively when run in an online judge. Thus it eliminates the need to edit the code, for reading from a file, and again for reading from stdin.

Refer to this video for more details : Setting up Sublime Text for Competitive Coding - YouTube

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thanks… finally got it :slight_smile:

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My pleasure

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One can watch the above video as well.It is good
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Thanks a lot! This link was of great help!

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Is it helpful in “interactive problems”?

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No, you can’t use it for an interactive problem. For interactive problems we’ve to use the inbuilt terminal.

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I didn’t get this sentence…i mean here we are pointing stdin to read from input.txt,that means we need to edit the code(commenting the online_judge) for reading from console right?

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I put that ifndef part in my c++ code. But after that no output is shown in the output file. What is the problem, I don’t understand

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check whether you have called the function or not. debugMode();