Today i came across a code which i am not able to understand.It would be great if someone could explain the output and behaviour of the code.
ans=i++ + ++i;
Now output of this code is 4.
I understand that increment operators have right to left associativity.
Now consider this code
ans=i++ * ++i;
output of this code is 3.
How? Why does it behave differently in these situations.Can someone please elaborate and explain how to both of the expressions evaluate???
Let’s analyse the case 1
ans=i++ (after this ans=1,i=2) as i++ first takes the current value of i for the current operation
and then increment it
ans=i++ + ++i(when you do ++i i becomes 3 from 2) as ++i first increment i and then take the incremented value of i for operation so
ans=1+3, this gives ans=4
Now for 2nd case
ans=i++ (ans=1,i=2) same as before
ans=i++ * ++i (i was 2 now becomes 3) same as before
so ans=1*3, this gives ans=3
It is often advised not to use ++/-- with same variable more than once in a single statement. Doing so results in compiler dependent behaviour. Which cannot be predicted using a pen and paper. Try running same commands on different compiler of c/c++. You will be definately surprised by the result.
Reason for this is due to undefined behaviour of +,-,*,/ sign. There is no hard and fast rule for these operators as to which side(left operator or right operator) should be executed first. As a result different compilers use different approaches for calculating answer.
A logic can be created to convince ourself with the answer but this cannot help us guarantee/ predict the result next time.
My advice, which I give to everyone who ask me these type of questions, here is Just avoid brainstorming with these type questions. Because there is lot more to learn.
Wait, I couln’t identify the problem.
i++ --> 1; i is now 2
++i --> 3; i is now 3
ans = 1 * 3 = 3
okay i understand now, i read in C by dennis Rithcie that associativity of ++ is from right to left so i thought it would increment from right to left, so i was confused