Links broken?
4 Likes
I used a different approach, I divided the string into two equal substrings by splitting it from the middle and then sorted both the substrings, since for true case (“YES”) the frequency of the characters in both the original substrings is same, so after sorting the substrings we should get identical substrings. So after sorting we just check if the sorted substrings are same of not. Here’s my solution :- CodeChef: Practical coding for everyone
15 Likes
can somebody trace bugs in my solution pls.
:- CodeChef: Practical coding for everyone
the program satisfies all test cases…
http://www.codechef.com/viewsolution/3258850
please tell the problem with my solution…
the given testcases for the question are giving the correct output…
and i have also tried some more test cases of my own…
but i am getting a wrong answer
@biprotip: Hey try to increase the size of the array. It is always better to increase the array size than the required. here 1 will be needed for the ‘\0’. And try with instead of using 2 variables use 2 array of size 26 and increase each index with left[ch[i]-‘a’]++ and same with the right array. Finally check if both the arrays are equal. If you have any doubt just look at this solution
1 Like
whats wrong with this code?
#include
#include
#include<string.h>
#include
using namespace std;
main(){
int t;
cin>>t;
for(int i=0;i<t;i++){
string s;
cin>>s;
int p=s.size()/2;
char A[p],B[p];
for(int j=0;j<p;j++){A[j]=s[j];}
for(int j=s.size()-1,k=0;j>=p;j–,k++){B[k]=s[j];}
sort(A,A+p);
sort(B,B+p);
vector v1§;
vector v2§;
vector ::iterator it1;
vector ::iterator it2;
it1=unique_copy(A,A+p,v1.begin());
it2=unique_copy(B,B+p,v2.begin());
v1.resize(it1-v1.begin());
v2.resize(it2-v2.begin());
//int p1=v1.size();
//sort(v1,v1+p1)
if(v1.size()!=v2.size()){cout<<“NO”<<endl;}
else{
int k1=0;
for(int j=0;j<v1.size();j++){
if(v1[j]!=v2[j]){k1++;}
}
int a[v1.size()],b[v2.size()];
for(int j=0;j<v1.size();j++){
int k2=0;
for(int k=0;k<p;k++){
if(v1[j]==A[k]){k2++;}
}
a[j]=k2;
}
for(int j=0;j<v2.size();j++){
int k2=0;
for(int k=0;k<p;k++){
if(v2[j]==B[k]){k2++;}
}
b[j]=k2;
}
int k3=0;
for(int j=0;j<v1.size();j++){
if(a[j]!=b[j]){k3++;}
}
if(k3>0 || k1>0){cout<<“NO”<<endl;}
else{cout<<“YES”<<endl;}
}
}
}
Its a bit difficult to have a good look over your code atm. I strongly advise that you either givea submission link to your code, or edit the post (select your code, and THEN press button “insert code”)
But by what I could get, I will say just make 2 arrays - int a[26], b[26] and increase the frequency of letters you encounter in the half of string.
Eg-
for (i= 0; i <n /2; i++)
{
arr[s[i]-‘a’]++;
}
EDIT: Something seems wrong with this insert code thing atm. I just cant make it write my code properly like I used to…
i am unable to find out error please help me
#include<stdio.h>
#include<string.h>
int main()
{
int t,c,start,end,flag,i;
char s[1000];
scanf("%d",&t);
while(t–)
{
flag=0;
scanf("%s",s);
c=strlen(s);
if(c%2==0)
start=c/2;
else
start=c/2+1;
end=c/2-1;for(i=0;i<=end;i++) { if(s[i]==s[start++]) continue; else{ flag=1; break; } } if(flag==0) printf("YES\n"); else printf("NO\n"); } return 0;}
Hey there, Can somebody solve my problem regarding LAPIN.
According to the question, zyzxyz is not lapindrome but my code, which has been accepted by the compiler gives YES to it.
I am confused…
import java.util.HashMap;
import java.util.Scanner;
class LAPIN {
public static void main(String[] args) throws Exception {
Scanner scanner = new Scanner(System.in);
int t = scanner.nextInt();
for (int i = 0; i < t; i++) {
String s = scanner.next();
int half = s.length() / 2;
String s1 = s.substring(0, half);
String s2 = s.substring(half, s.length());
HashMap<Character, Integer> map1 = new HashMap<Character, Integer>();
for (int j = 0; j < s1.length(); j++) {
if (!map1.containsKey(s1.charAt(j))) {
map1.put(s1.charAt(j), 1);
} else {
map1.put(s1.charAt(j), map1.get(s1.charAt(j) + 1));
}
}
HashMap<Character, Integer> map2 = new HashMap<Character, Integer>();
int k = s2.length() % 2 != 0 ? 1 : 0;
for (; k < s2.length(); k++) {
if (!map2.containsKey(s2.charAt(k))) {
map2.put(s2.charAt(k), 1);
} else {
map2.put(s2.charAt(k), map2.get(s2.charAt(k) + 1));
}
}
if (map1.equals(map2)) {
System.out.println(“YES”);
} else {
System.out.println(“NO”);
}
}
}
}
It passed all the test cases in my local but when I submit my code it showing the wrong answer. Can somebody help me, please
i got WA becoz i was priniting “Yes” instead of “YES” .
lol
2 Likes
Hello, pls anyone give me the test cases for which the following code doesn’t work : CodeChef: Practical coding for everyone ??
(LAPIN)
This satisfies all test cases but I get wrong answer.
Link to solution:
https://www.codechef.com/viewsolution/17144359
Help Me please !!
I am unable to find and rectify the error in the following :
#include <bits/stdc++.h>
#include <string>
using namespace std;
#define N 1000000007
#define ll long long
int main()
{
ll t;
cin>>t;
while(t--)
{
string s;
cin>>s;
ll l;
if(s.length()%2==0)
{
l=s.length()/2;
}
else{
l=(s.length()-1)/2;
}
char a1[l],a2[l];
if(s.length()%2==0)
{
for(int i=0;i<l;i++)
{
a1[i]=s[i];
a2[i]=s[i+l];
}
}
else{
for(int i=0;i<l;i++)
{
a1[i]=s[i];
a2[i]=s[i+l+1];
}
}
a1[l]='\0';
a2[l]='\0';
sort(a1,a1+l);
sort(a2,a2+l);
bool isSame=true;
for(int i=0;i<l;i++)
{
if(a1[i]!=a2[i])
{
isSame=false;
break;
}
}
if(isSame)
{
cout<<"YES\n";
}
else{
cout<<"NO\n";
}
}
return 0;
}
It is satisfying all test cases but getting a WA.