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We can help only after competition is over. Sorry.
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ouu np
but do pls clear my doubt after the competition
thanx for the reply
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Hey. The Editorial for the problem is here. You can check it out:
EQUALCOIN - Editorial - editorial - CodeChef Discuss
So many cases are not required.
if( x%2 | ( !x & y%2 ) ) cout<<"NO"<<"\n";
else cout<<"YES"<<"\n";
I think this should suffice just 3 conditions.