Need Help in checking Testcases for "Buying candies "

21

Thanks for quick response, please update the standings if possible.

22

hey, bud can u explain to me …in 3rd question i.e. “Poreee gelooo” how in the last test case i.e.
" adoreee gelooo" the answer is 30 and similarly how “baoreee gelooo” is 53.

23

yeah sure, first off ,it should be obvious that the second string is useless and the last 5 characters are redundant in the first string. So of the remaining letters like for " adoreee gelooo" the remaining string is “ad”, if you write “ad” in base 26 will be 14 (1->a and 4->b ), so the number 14_{26} will be 26*1+4 = 30 , similarly it’s 53 for “baoreee gelooo” . This code should make the idea clear,

AC_CODE 
#include <bits/stdc++.h>
using namespace std;
void solve(){
  int ans =0 ;
  string s,t ;
  cin >> s >> t  ;
  reverse(s.begin(),s.end()) ;
  string a = s.substr(5);
  for(int i=0,j=1;i<a.size();i++,j*=26)
    ans+=(a[i]-'a'+1)*j ;
  cout << ans << '\n' ;
}
signed main() {
  int t ;
  cin >> t ;
  while(t--)
    solve() ;
}
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24

Thanks for the explanation.