Yes, with a_1 = a_2 = a_3 = a_4 = a_5 = a_6 = 1 and a_7=2.

Can anyone help me out for which test case I am failing?

Kindly let me know any test case in which my program is not passing.

if ( (int)v.size() != 13 ) { // why 13

puts(“no”);

return 0;

}

```
for ( int i = 0; i < 7; i++ ) {
if ( v[i].first != i + 1 ) {
puts("no");
return 0;
}
}
for ( int i = 7; i < 13; i++ ) {
if ( v[i].first != 13 - i || v[i].second != v[12 - i].second ) {
puts("no");
return 0;
}
}
can someone explain me this?
```

This is my accepted solution for this question on Codechef

#include <bits/stdc++.h>

using namespace std;

int main()

{

long t;

cin>>t;

while(t–)

{

long n;

cin>>n;

int p[n],flag=1,i;

for(i=0;i<n;i++)

cin>>p[i];

int chec[8]={0};

```
for(i=0;i<n;i++)
chec[p[i]]++;
for(int i=1;i<7;i++)
{
if(chec[i]%2!=0||chec[i]==0||chec[7]==0)
{
flag=0;
break;
}
}
if(flag==0)
cout<<"no"<<endl;
else
cout<<"yes"<<endl;
```

}

return 0;

}

This is Author Solution for the same question

#include <bits/stdc++.h>

using namespace std;

const int MAXN = 105;

const int MAX = 100;

int a[MAXN];

int main() {

int T;

scanf("%d", &T);

assert(T >= 1 && T <= MAX);

while (T–) {

int n;

scanf("%d", &n);

assert(n >= 1 && n <= MAX);

for (int i = 0; i < n; i++) {

scanf("%d", &a[i]);

assert(a[i] >= 1 && a[i] <= MAX);

}

vector<pair<int, int> > cnts;

int cnt = 1, which = a[0];

for (int i = 1; i < n; i++) {

if (a[i] == a[i - 1]) {

cnt++;

} else {

cnts.push_back(make_pair(which, cnt));

which = a[i];

cnt = 1;

}

}

if (cnt > 0) {

cnts.push_back(make_pair(which, cnt));

}

int ok = true;

// cnt dentoes consecutive groups of equal numbers.

if (cnts.size() == 13) {

for (int i = 0; i < 13; i++) {

if (cnts[i] != cnts[13 - i - 1]) {

ok = false;

}

if (i < 7 && cnts[i].first != i + 1) {

ok = false;

}

}

} else {

ok = false;

}

puts(ok ? “yes” : “no”);

}

return 0;

}

Now Test case i have used is this

1

13

3 4 5 6 1 2 7 2 1 6 5 4 3

My accepted solution is giving yes for above test case while Author’s solution giving no for the same…

I have run several hundreds of codes of other people also for the same test case.Their answer is yes for above test .

But Editorial and Tester solution is giving no for the same.

Just want to ask Codechef Admins what is happening here .Even the guys who have made the question have not used the correct test cases for checking solutions.

I have spend hours on this test case

1

13

3 4 5 6 1 2 7 2 1 6 5 4 3

I think that problem setter has not used correct test cases for solution checking.

The answer should be `no`

; the testcases for this problem seem to be very weak.

https://www.codechef.com/viewsolution/30389060

can someone please check my code and spot what i am forgetting in my logic…it is giving wrong answer on task 0 ?

its outputting “yes”

I know

then sir what can be the problem…?

It should be outputting

`no`

why sir its incrementing by 1 from 1 and is follows rainbow rules…can you explain why please?

Read the question more closely What are the values of a_1,a_2, ... , a_7 for your testcase?

ok sir:)

Could anyone please point out which cases I am missing

https://www.codechef.com/viewsolution/30560990

I decremented the elements by 1 after each recursion and checked if the first and last a1 elements are equal to 1

It depends on the number of 7’s in in the sequence

If the number of 7’s are even then you have an even number of elements in the array otherwise odd.

what about 1 2 3 4 3 2 1?

My code gives yes, but one of the AC codes I compiled gives NO.