Can any body tell me how in this code iterator.second.first and iterator.first.second is accessing
This recent thread might be of some use:
2 Likes
could you explain it.second.first I only know about it.second usage
According to what I think,
Given:
map<a, pair<b,c>> it.second = pair<b,c> it.second.first = pair<b,c>.first = b
3 Likes
Thanks
1 Like