Can somebody please provide an editorial for the problem SIGNTURE.

Its a simple Brute Force since the constraints are smaller. Just check everything and see how many places differ. The main part of the code is something like this: Here A is Actual Signature Matrix and B is Given Signature Matrix. And if B[i][j] is out of bounds, its taken as ‘0’.

```
for(dr=-n;dr<n;dr++)
{
for(dc=-m;dc<m;dc++)
{
int a=0;
for(i=0;i<n;i++)
{
for(j=0;j<m;j++)
{
if(A[i][j]!=((i+dr>=0&&i+dr<n&&j+dc>=0&&j+dc<m)?B[i+dr][j+dc]:'0')) a++;
}
}
ans=min(ans,a);
}
}
```

Code: https://www.codechef.com/viewsolution/27937051

P.S. There’s a lot of unnecessary lines in there 'cause initially, I thought it will be more complex. But it’s just a brute force.

2 Likes

Thanks! I kept trying for long and it turns out to be this.