What does sigsegv runtime error means? In my case: it gave me sigsegv runtime error with more number of out put than I assigned to print out from an array in c code

Hello,below is my code turbo sort I do not know why I AM getting wrong output.it work fine when I run with my compiler #include<stdio.h> void sort(int **arr) { for(int i=0; i<(sizeof arr)-1; i++) { if(arr[i]>arr[i+1]) { int temp; temp=arr[i]; arr[i]=arr[i+1]; arr[i+1]=temp; } } } int mai…

The code has few syntax errors in it. Few things to mention:- In the function parameter, where you have taken a double-pointer, why double pointer? Even if you just pass arr[], it will work the same way. sizeof() will return the size of the array, which happens to be a number of elements multipl…

Merely compiling this as C++ would have revealed most of the issues: [simon@simon-laptop][10:32:59] [~/devel/hackerrank/otherpeoples]>./compile-latest-cpp.sh Compiling chintu_288-TSORT.cpp + g++ -std=c++14 chintu_288-TSORT.cpp -O3 -g3 -Wall -Wextra -Wconversion -DONLINE_JUDGE -D_GLIBCXX_DEBUG -fsa…

why i am getting run time error in this code to reverse an array? #include using namespace std; int main() { // your code goes here int N ; int arr[20]; cin>>N; for (int i=0;i<N;i++){ cin>>arr[i]; } for(int i=N-1;i>=0;i–){ cout<<arr[i]<<" "; } return 0; }

What test input are you giving it?

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Why segsig run time error ocuur

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c, sigsegv, sigsesv

cubefreak777 May 11, 2021, 8:24am 2

Why do I get a SIGSEGV? faq

This is an error caused by an invalid memory reference or segmentation fault. The most common causes are accessing an array element out of bounds, or using too much memory. Some things for you to try: Make sure you aren’t using variables that haven’t been initialised. These may be set to 0 on your computer, but aren’t guaranteed to be on the judge. Check every single occurrence of accessing an array element and see if it could possibly be out of bounds. Make sure you aren’t declaring too muc…

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