how do u calculate ans modulo all prime powers in M .??
Since prime power can be non prime ( i am assuming prime power means p^q)
So denominator and prime power can be non co prime too right ??
So how do you calculate modular inverse !!
how do u calculate ans modulo all prime powers in M .??
Since prime power can be non prime ( i am assuming prime power means p^q)
So denominator and prime power can be non co prime too right ??
So how do you calculate modular inverse !!
Yes N and K are not 10^18 in that testcase.
how ?? p^q is non prime right ?? lucas theorem works for only prime modulus right ?? Correct me if wrong !!
Can you please provide some source to read about Lucas Theorem and CRT?
so constraints were n,k <= 10^18 or the same as of subtask ,2??
How did you identify that (nk−n%k+knk)(nk−n%k+knk) is the solution? I would appreciate if you can explain that as well 
@c0d3h4ck3d Updated the answer with resources for both.
@vijju123 It was more of an observation, after writing a brute force algorithm.
it is, but in a paper of Andrew Granville, it has been extended to prime powers, and after that u need to use chinese remainder theorem
My brute force was too brute 
Here is how I derived the formula:
https://discuss.codechef.com/questions/98129/your-approach-to-solve-sandwich/98220
““Notice that we take out precisely (⌊x⁄pi⌋!)*pi out of the factorial””
Say x = 6. and p = 2.
(⌊x⁄pi⌋!)*pi = 12 now. But 6! has 16 as power of 2 . Am i right or wrong ??
@sanket407 The thing is we are taking out all the terms divisible by 2 out of 6!, not just the powers of 2.
These terms are 2,4 and 6. We are ignoring these terms as they have 2 as a factor.
The term that we are taking away is hence (⌊x⁄pi⌋!)×(pi^⌊x⁄pi⌋) (Sorry for the typo).
This is equal to 2×4×6 = 48 = 3! × 2^3.
So I calculate 6!/48 = 15
Note that 15 has no powers of 2.
Now as we ignored 2×4×6, it can be written as 3! * 2^3.
We remove the powers of 2 and do the same thing again for 3!
This gives us 3.
15×3=45
This is precisely 6! without any power of 2
That’s actually the generalized Lucas theorem (aka Granville theorem), seems like you were able to derive it during the contest, and that’s brilliant!
@hikarico I just read it. It really is the same. I actually didn’t derive it completely on my own. Just didn’t realize that this link that I referred to described the basic insight behind the generalized lucas’s theorem. https://goo.gl/JLyjAa