Hey Guys,
My answers,although not accurate are
Q1 a)74 b)67 c)65
Q2 a)3 b)2 c)4
Q3 a)20 b)16 c)96
Q4 (My answers are all wrong,missed out on a couple of cases) but the first subpart is 61 for sure
The approximate cutoff should be around 30-40 for Class X and below, 40-50 for Class XI and around 50 for Class XII.
All the best to everyone 
1.) 74 2.) 67 3.) 65 4.) 3 5.) 2 6.) 4 7.) 20 8.) 16 9.) 96 10.) 61 11.) 321 12.) 2671 I got these answers.
1-- 73[Looks like I messed up on this one:P ]; 2-- 65 3-- 67 ; 4 – 3 ; 5-- 2 ; 6 – 2[Sure about this; I know it is different from your answers]; 7-- 16; 8-- 13; 9 – 35; 10-- 73; 11-- 481; 12-- 4321. Let’s wait and see what happens. I think the cut off will be 60 for class 12 and 5 points less for every subsequent class.
Hey guys! My answers were :
74, 67, 65
3, 2, 4
20, 16, 96
49, 261, 1531
In my opinion, the paper was easier than the last year.
I expect the cutoff for class 12th to be about 60.
I got
1-3) 74, 67, 65
4-6) 5, 2, 5
7-9) -
10-12) 49, 261, 1531
My answers were:
(1) 74
(2) 67
(3) 65
(4) 3
(5) 2
(6) 4
(7) 20
(8) 16
(9) Did not attempt
(10) 61
(11) 321
(12) 671
Hello guys! My answers are-
1)74
2)67
3)65
4)3
5)2
6)4
7)18
8)16
9)84
10)48
11)120
12)240
My answers were:
- 95 86 86
- 3 2 4
- 20 15 90
- 49 261 1531
I know I screwed up first one.
Could somebody tell me how to do it.
Hey Guys, good exam.
Here are my answers
- 74, 67, 65
- 3, 2, 4
- 19, 16, 85
- 49, 261, (wrong answer for sure :P)
Can someone confirm the answers?
my answers are…
-
74, 74, 65
-
2, 2, 3
-
cant solve it
-
61, 321, 2311
I think I’ve done well myself. Was very worried in the morning. My answers:
- 74
- 67
- 65
- 3
- 2
- 2
- 20
- 16
- Forgot
- 49
- 261
- 1651
Does anybody have 2 as their answer in 4th and 6th? ( I got 2 but now I don’t remember how. I think I made a mistake or something)
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Hey my answers were as follows
1) 74 2) 67 3) 65 4) 3 5) 2 6) 4 7) 28 8) 9 9) 51 10) 49 11) 201 12) 957
I am getting 45. My first two questions and the first part of the last question is correct. I am in class 10th can someone please tell me the expected cutoff.
- 74, forgot, 65
- 3, 2, 4
- 20, forgot, forgot
- 49, 261, forgot
@saioneer3683 damn , we have the same answers for the last problem, let’s hope ours is right, can make all the difference!
1 Like
My answers
74
67
65
3
3
4
20
15
94
36
120
360
How did you solve 7,8,9 and 10,11,12
For 7,8,9 I used brute force
For 10,11,12 I used permutations and combinations
My Answers (To the best of my Recollection):
- 74, 67, 65
- 3, 2, 4
- 20, 16, 96
- 49, 261, 1531
The Questions were easy. Guess The cutoff should be 55/50
Logic for the Questions were:
- Group together values at indices with same remainder, Pick max value of each of K groups, Add.
- Greedily fill each position, values closest to 0 first (break into chunks of 10) and fill rest from end.
- Dynamic Program. Solve for last k elements, for any update add for all Good sub-strings ans of next.
- Write n as sum of no.s < 3. For each, count all permutations and divide by factorial of number of equal-sized groups.
@siddharth2000 I think its the same algo used in dividing a string into least no of palindromes I set the rightmost 1 position to value of 1 and then kept moving leftward and assume there is a partition there.Then if th selected position is 1 then the number of ways from this position is 1+(number of ways from next position) , if the selected positions value is 0 then find out the smallest possible continuous good string from this position and set its value to 1+(value of position just after the position of the smallest continuous good string). Answer is the sum of these numbers.I can’t say that it is completely correct as I figured this out only after 173 mins 