Why do I get a SIGSEGV?

Why I am getting a runtime error SIGSEGV in the problem? Where I am going wrong?

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This is an error caused by an invalid memory reference or segmentation fault. The most common causes are accessing an array element out of bounds, or using too much memory.

Some things for you to try:

Make sure you aren’t using variables that haven’t been initialised. These may be set to 0 on your computer, but aren’t guaranteed to be on the judge.

Check every single occurrence of accessing an array element and see if it could possibly be out of bounds.

Make sure you aren’t declaring too much memory. 64 MB is guaranteed, but having an array of size [10000][10000] will never work.

Make sure you aren’t declaring too much stack memory. Any large arrays should be declared globally, outside of any functions - putting an array of 100000 ints inside a function probably won’t work.

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//why i was getting SIGSEGV??
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//please help n explain

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can anyone help m why m getting SIGSEGV RUNTIME ERROR CodeChef: Practical coding for everyone

why di i get reutime error for given problem
#include<stdio.h>
#include<stdlib.h>
#define size 65535
int main()
{
long n,k,j,t[size],i=0,count=0;
scanf("%ld %ld",&n,&k);
while(i<n)
{
scanf("%ld",&t[i]);
printf("\n");
if(t[i]%k==0)
count++;
i++;
}
printf("%ld\n",count);
}

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why do i get SIGSEVG

why am i getting SIGSEVG ?
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can anyone help me…why i am getting SIGSEVG error in this PeQwg9 - Online C Compiler & Debugging Tool - Ideone.com
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can anyone help me…why i am getting SIGSEVG error in this PeQwg9 - Online C Compiler & Debugging Tool - Ideone.com
thanks in advance

#include<stdio.h>
main()
{
long long t=0,i=0,j=0,temp=0,a[10000];
scanf("%lld",&t);
for(i=0;i<t;i++)
scanf("%lld",&a[i]);

for(i=0;i<t-1;i++)
{
	for(j=0;j<t-1;j++)
	{
		if(a[j]>a[j+1])
        {
        temp=a[j];
		a[j]=a[j+1];
		a[j+1]=temp;
	    }
   }
}
for(i=0;i<t;i++)
  printf("%lld\n",a[i]);

}

why am i getting SIGSEVG ? CodeChef: Practical coding for everyone plzzzzz help me!! Thank U…

A segfault basically means you did something bad with pointers. This is probably a segfault:

char *c = NULL;

*c; // dereferencing a NULL pointer
Or this:

char *c = “Hello”;

c[10] = ‘z’; // out of bounds, or in this case, writing into read-only memory
Or maybe this:

char *c = new char[10];

delete [] c;

c[2] = ‘z’; // accessing freed memory
Same basic principle in each case - you’re doing something with memory that isn’t yours.

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Why do I get SIGSEGV error for this code CodeChef: Practical coding for everyone