this question was asked on hackerrank in my college contest mnitcodefriday .plzz explain me the solution…

all a,b,c,are integers and answers x,y will be ints also

find equation of line which is perpenducular to given line.

which is -bx+cy=d , you need to fine constant d.

since this line should pass to origin d will be zero.

so by solving this two equation -bx+cy=d and ax+by=c , you will get your answer.

According to #gandu007 … answer is …

x + 2y = 3, ax+by=c

-2x + 3y = 4, -bx+cy=d

2x + 4y = 6, 2 * ax+by=c

7y = 10

y = 10/7 => x = 1/7 … is the nearest point

@gandu007 thanks for your ans i am from mnit i needed to ask this thing too .i can’t believe that i forgot this thing . they teach it in school standard…

why -bx+cy are u taking the variables b and c same as in ax+by=c

and x>0 so if we get x<=0 then our ans is x=1,y=(c-a)/b…thanks for your ans

ohh my bad completely forgot slope thing(m1*m2=-1) thanks …

x=1,y=(3-1)/2=1

is correct x,y are ints and x>0

thanks anyway, for stopping by i am upvoting you so u can ask yours not for explanation of earlier answer

you can edit my answer, i forgot to mention that little thing. Thanks for pointing it out.