ACCURACY - EDITORIAL

editorial
,
1

PROBLEM LINK:

Contest Division 1
Contest Division 2
Contest Division 3
Contest Division 4

Setter: lavish_adm
Testers: gamegame
Editorialist: hrishik85

DIFFICULTY:

580

PREREQUISITES:

None

PROBLEM:

There are 100 questions in the paper

  • For each correct answer, Chef gets +3
  • For each wrong answer, Chef get -1 (negative marking)
  • For each unanswered question, Chef gets 0 points

What is the minimum number of problems Chef marked as incorrect given the score as N?

EXPLANATION:

Given a score N - For the minimum number of problems to be incorrect, the correct questions solved also need to be minimum.

The count of problems solved correctly will be (N / 3) rounded up to the nearest integer.
Score of problems solved correctly will be [{math.ceil (N/3)} * 3]
Problems solved incorrectly will be N - [{math.ceil (N/3)} * 3]

TIME COMPLEXITY:

Time complexity is O(1).

SOLUTION:

Editorialist's Solution 
import math

t=int(input())
for _ in range(t):
    n=int(input())
    z=math.ceil(n/3)
    print(3*z - n)
1 Like
2 
int x;cin>>x;
if (3-x%3==3) cout<<0<<endl;
else cout<<(3-x%3)<<endl;
1 Like
3

hey could you please tell me why are we subtracting 3