Problem Setter:Suhash Problem Tester: Editorialist:Sunny Aggarwal Contest Admin: Russian Translator: Mandarin Translator: Vietnamese Translator: Language Verifier:
DIFFICULTY:
Cakewalk
PREREQUISITES:
Simple, Input processing, Basic Maths.
PROBLEM:
Given a list of integers. We are asked to report whether the number of even integers is more than the number of odd integers or not.
EXPLANATION
This is a simple problem and can be solved by simply counting the number of even/odd integers.
Basic C++ Code:
int main() {
int n; cin >> n;
int cnt = 0;
for(int i=1; i<=n; i++) {
int x; cin >> x;
if( x % 2 == 0 ) cnt ++;
}
puts( cnt > n - cnt ? "READY FOR BATTLE" : "NOT READY" );
return 0;
}
Basic Java Code:
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int cnt = 0;
for(int i=1; i<=n; i++) {
int x;
x = sc.nextInt();
if( x % 2 == 0 ) {
cnt ++;
}
}
System.out.println( cnt > n - cnt ? "READY FOR BATTLE" : "NOT READY" );
}
Basic Python Code:
import sys
f = sys.stdin
n = int(f.readline())
cnt = 0
A = [int(x) for x in f.readline().split()]
for i in range(0, n):
if A[i] % 2 == 0:
cnt += 1
if cnt > n - cnt:
print "READY FOR BATTLE"
else:
print "NOT READY"
whats wrong with this code? why is it not entering the loop?
#include<stdio.h>
void main()
{
int N,i,b=0;
int A[100];
scanf("%d",&N);
for(i=1;i<=N;i++)
{
scanf("%d",&A[i]);
}
for(i=1;i<=N;i++)
{
if(A[i]%2==0)
b=b+1;
}
if(b>N-b)
printf(" ready for battle");
else
printf("not ready ");
}
