*Author:* noob_tech

*Tester:* noob_tech

*Editorialist:* noob_tech

# DIFFICULTY:

CAKEWALK, SIMPLE, EASY.

# PREREQUISITES:

Math .

# PROBLEM:

CodeMaster is given a Series pattern which is increasing in a particular manner.His teacher told him find the Nth term of the series.

2,8,18,32,50,72,….

Help the CodeMaster to find the Nth term of series and print Nth term.

# QUICK EXPLANATION:

We are given a series. If we are observed pattern that it increases in a particular manner i.e( (N*N)+(N*N) ). So use this formula (N*N)+(N*N) to find Nth term of series.

# EXPLANATION:

Here, We are given a series who increases in a particular manner i.e. 2,8,18,32,50,72,… We have to find the Nth term of the series.

Lets Consider N=3, For N=3 Output should be 18.

For this particular series we will use (N*N)+(N*N). That’s (3*3)+(3*3)=18.

So output will be 18.

# SOLUTIONS:

## Setter's Solution

#include<bits/stdc++.h>

using namespace std;

int main()

{

int t;

cin>>t;

while(t- -)

{

long long n,ans;

cin>>n;

ans=(n * n)+(n * n);

cout<<ans<<endl;

}

return 0;

}

## Tester's Solution

#include<bits/stdc++.h>

using namespace std;

int main()

{

int t;

cin>>t;

while(t- -)

{

long long n,ans;

cin>>n;

ans=(n * n)+(n * n);

cout<<ans<<endl;

}

return 0;

}

## Editorialist's Solution

#include<bits/stdc++.h>

using namespace std;

int main()

{

int t;

cin>>t;

while(t- -)

{

long long n,ans;

cin>>n;

ans=(n * n)+(n * n);

cout<<ans<<endl;

}

return 0;

}