# PROBLEM LINK

Practice

DeCode 2021 - 2 seconds left

* Author:* akcube, fangahawk

*Announcement*

**Tester:***akcube*

**Editorialist:**# DIFFICULTY

CAKEWALK

# PROBLEM

Given a set of N numbers, output their average. Find the bug in the code.

# BUGGY CODE

```
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int n;
cin >> n;
int sum = 0;
for(int i = 0; i < n; i++) {
int x;
cin >> x;
sum += x;
}
double ans = sum / n;
cout << fixed << setprecision(9) << ans << endl;
}
```

# QUICK EXPLANATION

The buggy code performs integer division, giving WA.

# EXPLANATION

The problem asks to output the average of N integers. The bug is that the code performs integer division on the sum of the N integers which takes the floor of the division before assigning it to the double variable. This gives WA. The intended solution is to input any set of N numbers (within constraints) whose sum is not divisible by N. More formally,

N

a_1, a_2, \dots, a_N

Such that (\sum_{i=1}^{N} a_i) \ mod \ N \neq 0

An example of such a test case:

```
3
2 3 5
```