#PROBLEM LINK:

**Author:** Ayush Nagal

#DIFFICULTY:

Easy

#PROBLEM:

Given an integer n, we have to print the given pattern containing n rows and n columns.

#EXPLANATION:

There will be an outer loop for the number of rows. Inside it, there will be two loops: one for spaces and the other one for #.

```
for(int i=0;i<n;i++)
{
for(int j=1;j<=n-i-1;j++)
printf(" ");
for(int j=0;j<=i;j++)
printf("#");
printf("\n");
}
```

#AUTHOR’S SOLUTION:

Author’s solution can be found here.