BC203 - Editorial

editorial
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#PROBLEM LINK:

Practice
Contest

Author: Ayush Nagal

#DIFFICULTY:
EASY

#PREREQUISITES:
String

#PROBLEM:
Given a positive integer n, a string s and an integer k. We need to print the new string by rotating the characters of s by k.

#EXPLANATION:
First of all, we need to extract the ASCII value of each character in the string s. After that, we add k to the ASCII value and take modulus by 26 so that ASCII value doesn’t exceed the range of alphabets.

for(int i=0;i<n;i++)
{
    if(s[i]>='a' && s[i]<='z')
    {
        int t=s[i]-'a';
        t+=k;
        t=t%26;
        s[i]=t+'a';
    }
    
      if(s[i]>='A' && s[i]<='Z')
       {
        int t=s[i]-'A';
        t+=k;
        t=t%26;
        s[i]=t+'A';
       }
    
    
}

As it is clear from the solution, whenever the ith character of s is an alphabet, we shift it by k.

#AUTHOR’S SOLUTION:
Author’s solution can be found here.

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