BETTEROPT (Allot Table) Editorial

editorial
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1

BETTEROPT(Allot Table)

Problem link -LINK
Author- Aagam Jain
Tester - Aman Gupta

Difficulty : Simple
Problem Tag : Implementation , String

Problem :
If a string only have “tea!” in their sentence then print “SERVE TEA”.
If a string only have “coffee!” in their sentence then print “SERVE COFFEE”.
If a string only have"beer!" in their sentence then print “SERVE BEER”.
Else print “DO NOT UNDERSTAND”.

Explanation :
Simple brute force approach use find or compare function of strings to solve this out.

My Solutions :

JAVA solution

import java.util.*;
import java.lang.*;
import java.io.*;
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc=new Scanner(System.in);
		int tc=sc.nextInt();
		String s=sc.nextLine();
		while(tc-->0)
		{
		     s=sc.nextLine();
		     boolean t=(s.contains("tea!"));
             boolean c=(s.contains("coffee!"));
             boolean b=(s.contains("beer!"));
             if(t & !c & !b)
             System.out.println("SERVE TEA");
             else if(!t & c & !b)
             System.out.println("SERVE COFFEE");
             else if(!t & !c & b)
             System.out.println("SERVE BEER");
             else 
             System.out.println("DO NOT UNDERSTAND");
		}
	}
}

C++ Solution
LINK

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