BROKENPHONE - Editorial

PROBLEM LINK:

Practice
Contest: Division 1
Contest: Division 2
Contest: Division 3
Contest: Division 4

Author: Jeevan Jyot Singh
Testers: Utkarsh Gupta, Hriday
Editorialist: Nishank Suresh

DIFFICULTY:

451

PREREQUISITES:

None

PROBLEM:

Uttu broke his phone. He can get it fixed for X rupees or buy a new one for Y rupees. Which option is cheaper?

EXPLANATION:

There are three cases:

  • If X \lt Y, print “Repair”
  • If X \gt Y, print “New phone”
  • If X = Y, print “Any”

The three cases can be checked using if conditions.

TIME COMPLEXITY

\mathcal{O}(1) per test case.

CODE:

Editorialist's code (Python)
for _ in range(int(input())):
    x, y = map(int, input().split())
    print('repair' if x < y else ('new phone' if x > y else 'any'))