# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* Jeevan Jyot Singh

*Utkarsh Gupta, Hriday*

**Testers:***Nishank Suresh*

**Editorialist:**# DIFFICULTY:

451

# PREREQUISITES:

None

# PROBLEM:

Uttu broke his phone. He can get it fixed for X rupees or buy a new one for Y rupees. Which option is cheaper?

# EXPLANATION:

There are three cases:

- If X \lt Y, print “Repair”
- If X \gt Y, print “New phone”
- If X = Y, print “Any”

The three cases can be checked using `if`

conditions.

# TIME COMPLEXITY

\mathcal{O}(1) per test case.

# CODE:

## Editorialist's code (Python)

```
for _ in range(int(input())):
x, y = map(int, input().split())
print('repair' if x < y else ('new phone' if x > y else 'any'))
```