Sir, I want to assign 0 in all element of array. for this I write a program.
if x[3]={0} is valid & all of this array element is 0. then in the given below program why error message comes in " int a[j]={0};" as int a[j] comes after assigning value in “j” . why my given below program is not run?
#include <stdio.h>
int main()
{
int i,j;
printf(“Enter the size of array=”);
scanf("%d",&j);
int a[j]={0};
printf(“your Number=”);
for(i=0;i<j;i++)
{
printf("%d, ",a[i]);
}
return 0;
}
To initialize all array elements to 0, you can do as following.
int a[10] = {};
In both cases, all array elements will be zero.
If you write k elements in bracket, the first k elements will be assigned accordingly and left elements will be assigned with the value zero.
The problem here:- J is not compile time constant that’s why it is showing error.
Actually J is not compile time constant. And this type of initialization is done during compile time.
what is compile time constant in c programing ?
j is not known when the compiler is compiling the program, as it is a variable entered by the user. This type of initialization is not supported in C. You can instead run a loop from i=0 to j-1 and set a[i]=0 in the loop.