c++ input exception handling

general
1

Hey everyone, I’m expecting a double value from the user

a and d are double values while the c is a char value

do

{
    cin >> a >> c >> b;
    if(!cin.good())
      cout << "enter" << endl;
}
while(!cin.bad());

if the user accidentally enters a character or anything(that is not a double or an integer) this method should ask for the input again but what it is doing is keep printing the string “enter”. Any suggestion how can I fix this. Thanks

2

I actually looked up to it, but couldnt figure anything out.

Using cin.good and cin.bad , I am clueless about them honestly, since I never had to use them anywhere.

But checking if user entered an integer or not can be done. You can take input as a string, check if ASCII values lie in range of [48,57] (i.e. range of [‘0’,‘9’]). Pay special attention for double, they have a decimal “.” . If its correct, then convert it into double/int and store it (Either manually via loop or inbuilt function if any)

1 Like
3

@vijju123 please answer bro

4

I don’t have to use cin.good I just want something that can ask input again if the given input is not double or integer

5

You can use infinite loop then. And if the input we got is proper, we can break out of it.