C program related help

help
1

include <stdio.h>

int main() {
int var = 0120;
printf(“%d”,var);

return 0;
}
In this above code I am getting 80 as output I am not getting that can anyone help me with that

1 Like
2

In C, when you prefix a number with a leading zero (0), it is treated as an octal (base-8) number rather than a decimal (base-10) number.

So, when you write:

int var = 0120;

You are actually initializing var with the octal value 120, which is equivalent to the decimal value 80. In octal notation, the digit 8 is not valid, so it stops at 7, and 0120 in octal is equal to 80 in decimal.

That’s why when you print var using

printf("%d", var);

it prints 80.

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3

Thanks

1 Like
4

when we put 0 in starting in C program it treats it as Octal number. to print correct output use %o instead of %d.

include <stdio.h>

int main() {

int var = 0120;

printf(“%o”,var);

return 0;

}

5

Well, there is a simple syntax error with your code.
Try this code:

#include <stdio.h>

int main() {
    int var = 120;
    printf("%d", var);

    return 0;
}

Run the above code, and you will get what you are looking for.
Thanks