Firstly, link the problem and your submission instead of posting a screenshot.
Coming to your solution, changing the
break; should solve the issue. When you’re continuing after declaring the flag as 0, the flag can subsequently become 1, and you’ll be printing a “YES” when the answer is actually “NO”.
Another thing that I notice is that the difference logic is not quite right. You are supposed to subtract the change that chef gives from minchange. By adding a positive value to minchange everytime, it just keeps growing and Chef would never run out of coins.
Take the test case 5\;10\;5\;10\;5\;10\;10 for i = 5 your minchange = 30 and diff = 0. Here you’re trying to print “YES”, but Chef has actually run out of coins, and cannot give change to the last person!
thanks for help buddy it is really awesome explanation