#include<stdio.h>
int fib(int n)
{
int i;
if(n==1)
return(0);
if(n==2)
return(1);
else
return(fib(n-1)+fib(n-2));
}
void main()
{
int n;
printf("no of terms");
scanf("%d",&n);
for(int i=1;i<=n;i++)
printf("%d ",fib(n));
}
#include<stdio.h>
int fib(int n)
{
int i;
if(n==1)
return(0);
if(n==2)
return(1);
else
return(fib(n-1)+fib(n-2));
}
void main()
{
int n;
printf("no of terms");
scanf("%d",&n);
for(int i=1;i<=n;i++)
printf("%d ",fib(n));
}
Yes you can get , with the help of recursion.